$(20,21,x) \\Pythagoras -Theorem =\\a^2+b^2 = c^2\\\\20^2 + 21^2 = x^2\\400 + 441 = x^2\\841 = x^2\\Square -root-both-sides\\\sqrt{841} = \sqrt{x^2} \\29 = x\\\\x = 29$

6 0

3 years ago

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-6+x/x^4 limit at x →0

Jlenok [28]

Answer:

not existing

Step-by-step explanation:

$\frac{ - 6 + x}{ {x}^{4} }$

lim x goes to 0 is

$\frac{ - 6 + 0}{ {0}^{4} } = \frac{ - 6}{0}$

so not exist

I'm not sure if u mean that or this

7 0

3 years ago

A software designer is mapping the streets for a new racing game. All of the streets are depicted as either perpendicular or par

Mama L [17]

Its B -1.5x − 3.5y = -31.5

7 0

3 years ago

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