Question

Complex number in standard form

Answer 1

Answer:

Choice B is the answer.

Step-by-step explanation:

We have given an expression.

$(3i-\frac{2}{3})-(6i-5)$

We have to simplify it and write it as complex number in standard form.

a+bi is a complex number in standard form.

$3i-\frac{2}{3}-6i+5$

Adding like terms, we have

$(-\frac{2}{3}+5)+(3-6)i$

$(\frac{-2+15}{3})+(-3)i$

$(\frac{13}{3})+(-3)i$

$\frac{13}{3}-3i$ which is standard form of complex number.

Answer 2

Answer:

B. (13/3 - 3i)

Step-by-step explanation:

Given: (3i - 2/3) - (6i - 5)

Here we have to subtract.

To simplify we have to combine real numbers and complex number(i.e) terms with "i"

= 3i - 2/3 -6i + 5 [distributed the negative sign inside the parenthesis]

=  -2/3 + 5  + 3i - 6i[Combine real numbers and complex numbers]

=  13/3 - 3i

Therefore, the answer is B. (13/3 - 3i)

Hope this will helpful.

Thank you.