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4 years ago

Choose the correct simplification of the expression (8x2)3.

Mathematics

2 answers:

UNO [17]4 years ago

7 0

Simplify the expression and you get 512x^6.
Hope this helps.

REY [17]4 years ago

3 0

Answer:

( 8x²)³ = 512 $x^{6}$ .

Step-by-step explanation:

Given : ( 8x²)³.

To find : simplification.

Solution : We have given that ( 8x²)³.

We can write it (8)³ * (x²)³.

⇒ 512 $x^{6}$ .

Therefore, ( 8x²)³ = 512 $x^{6}$ .

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A car travels 0.75 miles every minute. Explain how you could use proportional reasoning to find how far the car travels in one h

Yuliya22 [10]

Answer:

Step-by-step explanation:

3990

5 0

3 years ago

Read 2 more answers

Two angles in a triangle are 30 degrees and 40 degrees. Find the missing angle measure. Please show your math work step by step

brilliants [131]

Answer:

110

Step-by-step explanation:

Hello There!

If you didn't know the rule about angles in a triangle is that they have a sum of 180

So we can find the measure of the missing angle by subtracting the given angles (in this case 30 and 40) from 180

so the missing angle = 180 - 30 - 40

180 - 30 = 150

150 - 40 = 110

so the missing angle = 110

5 0

3 years ago

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

3 years ago

Algebra II Help??? Subtracting Fractions<br><br> (2x)/(y^2-x^2) - (x)/(y-x)

denis23 [38]

Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
$\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}$ =
$\frac{2x-x(x+y)}{y^2-x^2}$ =
$\frac{2x-x^2-xy}{y^2-x^2}$

4 0

3 years ago

A bacteria culture contains 1500 bacteria initially and doubles every hour. (a) Find a function N that models the number of bact

Tpy6a [65]

Answer: a) $N(t)=1500(2)^t$

b) 25165824000

Step-by-step explanation:

The exponential equation for growth is given by :-

$y= ab^t$ , where a= initial value , b =multiplicative growth factor and t = time.

Given : A bacteria culture contains 1500 bacteria initially and doubles every hour.

i.e. a = 1500 and b= 2

Then, the function N that models the number of bacteria after t hours will be :

$N(t)=1500(2)^t$

To find , the number of bacteria after 24 hours , we put t= 24 in above equation , we get

$N(24)=1500(2)^{24}\\\\=1500(16777216)=25165824000$

Hence, the number of bacteria after 24 hours is 25165824000.

7 0

3 years ago