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Dovator [93]
3 years ago
13

Issac made a mistake in his checkbook. he wrote a check for $8.98 to rent a video game but mistakenly recorded it in his checkbo

ok as an $8.98 deposit. represent each transaction with a rational number and explain the difference between the transactions. Use absolute value to explain how a debit of $8.98 and a credit of $8.98 are similar.
Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0
Debit is where you have to pay extra when you use it. Credit doesn't!!!!!
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Is this correct ????<br><br> if no please let me know...thanks
UkoKoshka [18]
Yes i believe it is correct
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3 years ago
X+ y +z = 37
telo118 [61]

Answer:

C

Step-by-step explanation:

I'm not sure of my answer i hope it helps

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1 question geometry, thanks :)
Yuri [45]

Point B is located at (-6, 5)

Multiply each coordinate by the scale factor 3 to get

-6*3 = -18

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The point B' is located at (-18, 15)

3 0
3 years ago
Answer the following: GCF of 20 &amp; 32 GCF of 45 &amp; 75
Jet001 [13]

Answer:

GCF OF 20 AND 32: 4

Gcf of 45 and 75: 15

Step-by-step explanation:

GcF of 20 and 32

Factors of 20: 1, 2, 4, 5, 10, 20

Factors of 32: 1, 2, 4, 8, 16, 32

COMMON FACTORS: 1, 2, 4

GCF:4

Gcf of 45 and 75

Factors of 45: 15, 9, 5, 3, 1.

Factors of 75: 25, 15, 5, 3, 1.

CommoN factors: 1, 3, 5, 15

GCF:15

HOPE OT HELPED

3 0
3 years ago
Read 2 more answers
Ví dụ 1.5. Một người đi mua hàng 3 lần. Xác suất lần đầu mua được hàng tốt là 0,7.
vodka [1.7K]

Answer:

a) 0.50575,

b) 0.042

Step-by-step explanation:

Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.

If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).

And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:

a) All three times the person bought good goods.

P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =

(0.7)(0.85)(0.85) =

0.50575      

b) Only the second time that person buys a bad product.

P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =

(0.7)(1-0.85)(1-0.6) =

(0.7)(0.15)(0.4) =

0.042

5 0
3 years ago
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