Here are the scores of students on a history test. 57,58,61,61,65,71,73,75,77,78,80,82,92 Notice that the scores are ordered fro
trasher [3.6K]
I hope this helps the five numbers on the bottom 71 7374 7577 is the interquartile range
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
-2y, -2xy
Step-by-step explanation:
got it correct on the assignment :)
Answer:
.20$
Step-by-step explanation:
4 1/2=4.5
4.5 divided by 22.50=.20
