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tigry1 [53]
3 years ago
13

3x(x²-5) what's the product​

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0
3x(x^2 - 5)
(3x)(x^2 + 5)
(3x)(x^2) + (3x)(-5)
Thus, your answer would be: 3x^3 -15x
fenix001 [56]3 years ago
3 0

3x(x²-5)

Multiply the bracket by 3x

(3x)(x^2)=3x^3

(3x)(-5)=15x

Answer: 3x^3+15x

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The circle below is centered at (3 1) and has a radius of 2 what is its equation
Dominik [7]

Answer:

(x-3)^2 + (y-1)^2 = 4

Step-by-step explanation:

The equation of a circle is usually written in the form

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

The center is at the origin so (h,k) = (3,1) and  the radius is 2 so r=2

(x-3)^2 + (y-1)^2 = 2^2

(x-3)^2 + (y-1)^2 = 4

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Solve: 3(w – 2) ˃ 6w – 12
nignag [31]
Your answer is w < 2 hope this helps
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3 years ago
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Pls help ;-;<br> Solve for m∠B and m∠C in the parallelogram.<br><br> m∠B = ?°<br> m∠C = ?°
Ivahew [28]

Answer:

m∠B = 121

m∠C = 59

Step-by-step explanation:

Angle B:

(10x - 19) = (7x+23)\\10x+(- 19+19) = 7x+(23+19)\\10x=7x+42\\(10x-7x) = (7x-7x)+42\\3x = 42\\3x/3 = 42/3\\x = 14

10(14)-19 = 140-19 = 121

Angle C:

(121)2 = 242

360-242 = 118

118/2 = 59

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make 3/12 1/4 and make 2/3 4/6 then find the lcm of those number


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HELP!!!<br> With working out... what’s the values of a b and c<br><br> (2x+1)(ax+b)=(6x^2-5x+c)
Lady bird [3.3K]

Answer:

Step-by-step explanation:

(2x + 1)(ax + b) = 6x² - 5x + c

Expand the left side and put that half into standard form:

2ax² + 2bx + ax + b = 6x² - 5x + c

2ax² + (2b + a)x + b = 6x² - 5x + c

So now look at the x terms. We have "2a" x² on left and 6 x² on right, so:

2a = 6

a = 3

Then look at the x terms, those coefficients will then be equal:

2b + a = -5

2b + 3 = -5

2b = -8

b = -4

and finally, then non-x terms are equal:

b = c

-4 = c

so:

a = 3, b = -4, c = -4

4 0
3 years ago
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