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3 years ago

What is the the slope that passes through the points (4,-7) and (9,1)

Mathematics

2 answers:

monitta3 years ago

8 0

Answer:

The answer is 8/5

bulgar [2K]3 years ago

3 0

Answer:

8/5

Step-by-step explanation:

We can use the formula for finding slope for this: $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\frac{1 - (-7)}{9 - 4}$

$\frac{8}{5}$

The answer would be 8/5

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Little bit more math hw

Brut [27]

Answer:

$x=-2$

Step-by-step explanation:

For these kind of problems, simply take the denominator and compare it to zero. Then solve the equation.

$x+2=0\\\\\Rightarrow x=-2$ By subtracting 2 from both sides!

Best Regards!

5 0

3 years ago

What is y + 11 = 1/3(x + 3) in standard form?

lorasvet [3.4K]

Standard form is y=Mx+b so first step is to isolate y:
Y=1/3(x+3)-11

Then use order of operations to simplify the x to a whole number. First multiply by three:
3y=x+3-33

Now combine like terms:
3y=x-30

Finally,
Divide to make y have a coefficient if one:

Y= 1/3x -10

3 0

3 years ago

HURRY PLS!!!!!!!!!!!!!<br> !!!!!!!!!!!!!!!!!

lubasha [3.4K]

Answer:

diolation with s scale greayter than 1 is the answer

Step-by-step explanation: diolation is a flip and double

3 0

3 years ago

A Wooden board is leaning against the house the base of the board is 10 feet from the base of the house and the base of the boar

astra-53 [7]

Answer: 12.20 feet.

Step-by-step explanation:

Observe in the figure attached that a right triangle is formed.

Then, you need to remember the identity:

$cos\alpha=\frac{adjacent}{hypotenuse}$

In this case you can identify that:

$adjacent=10\\hypotenuse=x$

$\alpha=35\°$

Then, to find the length of the wooden board (x), you need to substitute values and solve for x.

Therefore, you get:

$cos(35\°)=\frac{10}{x}\\\\(x)(cos(35\°))=10\\\\x=\frac{10}{cos(35\°)}\\\\x=12.20$

The length of the wooden board is: 12.20 feet.

5 0

3 years ago

Find an expression for a cubic function f if f(4) = 96 and f(-4) = f(0) = f(5) = 0. Part 1 of 4 A cubic function generally has t

Bezzdna [24]

Given a polynomial $p(x)$ and a point $x_0$ , we have that

$p(x_0) = 0 \iff (x-x_0) \text{\ divides\ } p(x)$

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

$(x+4)(x)(x-5) = x(x+4)(x-5)$

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

$f(x) = ax(x+4)(x-5),\quad a \in \mathbb{R}$

To fix the correct value for a, we impose $f(4)=96$ :

$f(4) = 4a(4+4)(4-5) = -32a = 96$

And so we must impose

$-32a=96 \iff a = -\dfrac{96}{32} = -3$

So, the function we're looking for is

$f(x) = -3x(x+4)(x-5)=-3x^3+3x^2+60x$

4 0

3 years ago