All categories

3 years ago

Subtract 4’ 1” - 3’ 7”

Mathematics

1 answer:

Tatiana [17]3 years ago

7 0

Answer: 25/7

Decimal form 3.57143.....

You might be interested in

((Recall: 1 oz = 28.4 g. and 1 kg. = 1,000 g.) 100 oz ~ kg.

swat32

Since 1 oz is equal to 28.4 g and 1 kg is equal to 1000 g that means that 3521.12 kg are equal to 100 oz

4 0

3 years ago

Math question

strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0

3 years ago

What is the common rule for simplifying a negative exponent with a coefficient?<br> Ex: 3^-1

rjkz [21]

Anything to a negative power becomes the inverse with the coefficient to a positive power.
For example, 3^-1 becomes 1/3^1 or just 1/3.
3^-2 would be 1/3^2 or 1/9.

3 0

3 years ago

Read 2 more answers

PLEASE HELP IMAGE BELOW

gtnhenbr [62]

Answer:

Q1) ans-16%

Q2) ans-50%

Q3) ans- 16%

Q4) yes, I think the question 3 and 1 are same

5 0

2 years ago

I have a bottle of 3 l and a bottle of 5 l. How can I lose 7 l?

stiv31 [10]

Answer:

fill the 5l bottle up completely

pour the contents of the 5l bottle into the 3l until completely full

this should leave you with 2 litres in the 5 l bottle

empty out the water in the 3 litre bottle and then pour in the 2 litres

fill the 5 litre up completely and you have 7 litres

Step-by-step explanation:

3 0

2 years ago