I need the equation to be able to help
1) Let x be the original speed that he was driving;
x mph ---> 1.5 hours
x+44 mph --> 2.5 hours
1.5x + 2.5(x+44)=206
1.5x+2.5x+110=206
4x=206-110
4x=96
x=24
Therefore, he was travelling at 24 mph in the fog.
2) Let x be the speed of 1 snail,
The other snail travels at the speed of x+1 cm/min
23x+23(x+1)=391 <-- solve for x
23x+23x+23=391
46x=368
x=368/46
x=8
Therefore one of the snail travels at 8 cm/min while the other goes at 9 cm/min
7) Let x be one crew
Then the other crew would be working at x+0.5
3.2x+3.2(x0.5)=8 <-- solve for x
3.2x+1.6x=8
4.8x=8
x=8/4.8
x=1.6666 or 1.7 miles
Therefore, one of the crew does 1.7 miles per day and the other crew does (0.5*1.7)=0.85 miles
Hope I helped :)
The answer would be 1 3/14
Answer:
t = 6.3
Step-by-step explanation:
N=Noe^(-kt)
No = 14 grams
k = .1092
We want to find t when N = 7 or 1/2 of 14
N=Noe^(-kt)
7 = 14 e ^ (-.1092t)
Divide each side by 14
1/2 = e ^ (-.1092t)
take the natural log of each side
ln (1/2) = ln e ^ (-.1092t)
ln (1/2) = -.1092t
Divide each side by -.1092
ln (1/2)/ -.1092 = t
t≈6.3475
Rounding to the nearest tenth
t = 6.3
