<h3>Answer: approximately 63.43 degrees</h3>
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Work Shown:
Locate the intersection points
f(x) = g(x)
x^2 + 2x + 1 = 1
x^2 + 2x = 1-1
x^2 + 2x = 0
x(x+2) = 0
x = 0 or x+2 = 0
x = 0 or x = -2
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Compute the derivative
f(x) = x^2 + 2x + 1
f ' (x) = 2x + 2
Then plug in each solution x value we found earlier
f ' (0) = 2(0) + 2 = 2
The slope of the tangent line at the intersection point (0,1) is m = 2
The tangent line is y = 2x+1
The angle between the lines y = 1 and y = 2x+1 is arctan(2) = 63.43 degrees approximately
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Plug x = -2 into the derivative function
f ' (x) = 2x+2
f ' (-2) = 2(-2)+2
f ' (-2) = -2
The slope of the tangent line at (-2,1) is m = -2
The tangent line here is y = -2x-3
The angle between the lines y = 1 and y = -2x-3 is also 63.43 through similar reasoning as before.
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See the diagram below.
Your answer is 27.31 because u multiply 25.95 by 5.25 then divide it by 100 then add 25.95 to it
Answer:
20
Step-by-step explanation:
5[8(7−4)÷6]
5[8(3)/6]
5{24/6]
5[4]
20
Answer:
3x = 24?
Step-by-step explanation:
sorry I dont get what im supposed to be anwsering