How do you solve the area for a trapezoid?
1 answer:
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Let's take this variable by variable. z to the power of 4 over z to the power of one would equal z to the power of 3. At this point, there is no longer a z variable in the denominator.
X to the power of 2 over x to the power of 1 would equal x. At this point there is also no x variable in the denominator.
Y to the power of 1 over y to the power of 2 would equal (1/y). At this point, there is no y in the NUMERATOR.
Final Answer:
X to the power of 2 over x to the power of 1 would equal x. At this point there is also no x variable in the denominator.
Y to the power of 1 over y to the power of 2 would equal (1/y). At this point, there is no y in the NUMERATOR.
Final Answer:
The equation of the hyperbola is
The points on the graph are given as:
- (2, 0) and (-2, 0)
- (4, 0) and (-4, 0)
- Lines at: x = 1 and x = -1
The hyperbola can be represented as:
The points (2, 0) and (-2, 0) means that:
Square both sides
So, we have:
Also, we have:
a^2 = c^2 - b^2
Where c = 4
This gives
a^2 = 4^2 - 4
Evaluate
a^2 = 12
Substitute a^2 = 12 in
Hence, the equation of the hyperbola is
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