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3 years ago

How do you find Cosine when using trig?

Mathematics

2 answers:

loris [4]3 years ago

7 0

Answer:

cosine= <u>adjacent</u>

hypotenuse

mrs_skeptik [129]3 years ago

7 0

Answer:

adjacend/hypotonus

Step-by-step explanation:

When you want to find the cosine of an angle, you would divide the ajasent side by the hypotonus. You can remember soh cah toa for all the trig funtions. Hope this helps!

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Apply the square root principle to solve (x-5)^2-40=0

Nitella [24]

Answer: {5 ± 2√10, 5 - 2√10}

Step-by-step explanation: First isolate the binomial squared by adding 40 to both sides to get (x - 5)² = 40.

Next, square root both sides to get x - 5 = ± √40.

Notice that root of 40 can be broken down to 2√10.

So we have x - 5 = ± 2√10.

To get <em>x</em> by itself, add 5 to both sides to get x = 5 ± 2√10.

So our answer is just {5 ± 2√10, 5 - 2√10}.

As a matter of form, the number will always come before the

radical term in your answer to these types of problems.

In other words, we use 5 ± 2√10 instead of ± 2√10 + 5.

4 0

3 years ago

A group of students are randomly placed in either a traditional AP Stat class or an online-only AP Stat class. Both classes take

BaLLatris [955]

Answer:

Mean or Expected Value:

∑

(

)

Standard Deviation:

√

∑

(

−

)

(

)

Step-by-step explanation:

8 0

3 years ago

Newton’s law of cooling states that the temperature of an object changes at a rate proportionalto the difference between the tem

Verizon [17]

Answer:

$\frac{dT}{dt} = -0.05\;min^{-1} (T-70\ºF)$

Step-by-step explanation:

Hi!

Lets call:

T = temprature of the object

T₀ = temperature of surroundings

t = time

The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

$\frac{dT}{dt} = -k(T-T_0) \\$

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

$\frac{dT}{dt} = -0.05\;min^{-1} (T-70\ºF)$

3 0

3 years ago

Help, this is a khan question so you may have done it before

Readme [11.4K]

Answer:

Eric, 9.8 meters.

Step-by-step explanation:

Use the distance formula with the given coordinate and each of the other coordinate.

$\sqrt{(10-3)^{2}+(8-2)^{2} }$ Brooke

$\sqrt{(-6-3)^{2}+(6-2)^{2} }$ Eric

$\sqrt{(8-3)^{2}+(-6-2)^{2} }$ Cam

You'll see that Eric kicked the furthest distance with a distance of 9.8 meters.

Brooke kicked 9.2 meters and Cam kicked 9.4 meters. What does the distance formula really mean? When you solve for the distance between two points, you're really just creating a triangle between those two points, and you're actually looking for the hypotenuse. The slope that intersects your two points is the hypotenuse of the triangle you created.

8 0

3 years ago

A boat can travel at an average speed of 10 miles per hour in still water. Traveling with the current, it can travel 6 miles in

oksano4ka [1.4K]

Answer: The speed of the current is 2 miles per hour.

Step-by-step explanation:

We know that the speed of the boat is:

S = 10 mph.

When the boat travels with the current, the speed will be:

S = 10mph + x

where x = speed of the current.

When the boat travels against the current, the speed will be:

S = 10mph - x

Now, for a given amount of time T, when the boat travels with the current, it moves a distance of 6 miles.

Then we have the equation:

(10mph + x)*T = 6mi

And against the current, in the same time the boat moves 4 mi, then:

(10 mph - x)*T = 4mi

Then we have the system of equations:

(10mph + x)*T = 6mi

(10 mph - x)*T = 4mi

Now, we can take the quotient of these two equations and get:

((10mph + x)*T)/((10 mph - x)*T) = (6mi/4mi)

(10mph + x)/(10 mph - x) = 3/2

Now we can solve this for x.

(10mph + x) = (3/2)*(10 mph - x)

10mph + x = (3/2)*10mph - (3/2)*x

x + (3/2)*x = (3/2)*10mph - 10mph

(5/2)*x = (1/2)*10mph = 5mph

x = (2/5)*5mph = 2mph.

The speed of the current is 2 miles per hour.

6 0

3 years ago

Read 2 more answers