Answer:
The three components used by defense in depth strategy are:
1) Physical controls
2) Technical controls
3) Adminstrative controls
Explanation:
Defense in depth is a strategy using multiple security measures to protect to protect the integrity of information. Today's cyberthreat are evolving and growing rapidly. Defense in depth is a solid, comprehensive approach to utilizing a combination of advanced security tools to protect critical data and block threats before they reach endpoint.
If one line of defense is compromised, additional layers of defense are in place to ensure that cracks don't slip through the cracks.
Defense in depth strategy uses three components which are:
* physical controls: are anything that physically limits or prevents access to IT systems. Examples are security guards and locked doors.
* Technical controls: are hardware or software whose purpose is to protect systems and resources. Examples are disk encryption, fingerprint readers and authentication.
* Adminstrative controls: are an organization's policies and procedures which ensures that there is proper guidance are available in regards to security and that regulations are met. Examples are hiring practices and data handling procedures.
Answer: Extraction phase
Explanation: Transactional database is the data collection capable of undoing the transaction that has not been correctly done. Data warehouse id the place where transaction data is transmitted where different types of databases are stored.
The transmission of the information from transactional database to data warehouse is defined in the extraction phase.The extraction phase works by transforming the data into a particular format. It copes the transactional databases's data to the warehouse by making separate space for deposition of data
3-4 minutes is about right is say
Answer:
Question 1 :Write a program to enter a number and test if it is greater than 45.6 Example:
Answer:
#include <iostream>
using namespace std;
int main()
{
int user_number=0;
cout<<"Enter a number ";
cin >> user_number;
if(user_number >45.6){
cout <<"Greater than 45.6";
}
return 0;
}
Question 2: Test if a number grade is an A (greater than or equal to 90). If so print "Great!"
Answer:
#include <iostream>
using namespace std;
int main()
{
int user_number=0;
cout<<"Enter a number ";
cin >> user_number;
if(user_number >= 90){
cout <<"Great";
}
return 0;
}
Question 3:
Test if a password entered is correct. The secret phrase is Ada Lovelace.
Answer:
#include <iostream>
#include <string>
using namespace std;
int main()
{string pass_phrase ="Ada Lovelace";
string user_password="";
cout<<"Enter password ";
getline (cin, user_password);
if(user_password == pass_phrase){
cout <<"Correct";
}
else{
cout <<"Incorrect";
}
return 0;
}
Explanation:
Answer:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int a=1;
while(a==1){
float P=0.0,R=0.0,T=0.0,A=0.0,n=0.0,nt=0.0;
cout<<"Enter your Initial Investment Amount : ";
cin>>P;
cout<<"Enter your Rate of Annual interest : ";
cin>>R;
cout<<"Enter No. of times the interest is compound : " ;
cin>>n;
cout<<"Enter Time (years) : ";
cin>>T;
nt=n*T;
A=P*pow((1+R/n),(nt));
cout<<"After "<<T<<" years, the initial investment of "<<P<<" is : "<<A;
cout<<"\nEnter 1 to continue or exit by pressing any other button";
cin>>a;
}
return 0;
}
Explanation:
- Get the essential values from user as an input and store them in variables.
- Apply the following formulas to calculate years and initial investment.
- nt=n*T;
- A=P*pow((1+R/n),(nt));
- Finally display the results.