Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
Answer:
5 2/5
Step-by-step explanation:
(2 1/4) / x = (1 1/2) / (3 3/5)
so
x = (2 1/4) * (3 3/5) / (1 1/2)
First one single solution second no solution 3rd one single forth one infinity and last 2 are single and infinity
3,200,00 converted to scientific notation is 3.2 x 106