First, we should add 1 to both sides to isolate the variable:
3x = 12
Now that x is isolated, we divide by 3:
x = 4
That isn’t a question it is a statement
Answer:
Yumiko should multiply the other equation by 3.
If she adds the two equations she would be left with the variable 'x'.
Step-by-step explanation:
Given the two equations are as follows:


It is given that she multiplies the first equation by 6. Therefore, (1) becomes

Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.
The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.
Therefore, Equation (2) becomes:

Now, we add Equation (a) and Equation (b).


Factor: 3
Equation: 27x = 126
<h3>
Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>
A bit of further explanation:
The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.
Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h
For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.
Answer:
Parallel line:

Perpendicular line:

Step-by-step explanation:
we are given equation 4x+5y=19
Firstly, we will solve for y

we can change it into y=mx+b form


so,

Parallel line:
we know that slope of two parallel lines are always same
so,

Let's assume parallel line passes through (1,1)
now, we can find equation of line

we can plug values

now, we can solve for y

Perpendicular line:
we know that slope of perpendicular line is -1/m
so, we get slope as

Let's assume perpendicular line passes through (2,2)
now, we can find equation of line

we can plug values

now, we can solve for y
