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laila [671]
3 years ago
13

Find the circumference of a sphere's great circle with a radius of 4 m.

Mathematics
1 answer:
Ulleksa [173]3 years ago
3 0
This is the concept of areas and circumference of the solid figures;
The circumference of the cylinder whose radius is 4 m will be given by;
C=2πr
C=2*π*4
C=8π m=25.133 m
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3x-1=11 solve for the variable
artcher [175]

First, we should add 1 to both sides to isolate the variable:

3x = 12

Now that x is isolated, we divide by 3:

x = 4

6 0
3 years ago
One three and six are traingular list all the other triangular numbers up to 36
ArbitrLikvidat [17]
That isn’t a question it is a statement
3 0
3 years ago
As a first step in solving the system shown, Yumiko multiplies both sides of the equation 2x – 3y = 12 by 6. By what factor shou
GenaCL600 [577]

Answer:

Yumiko should multiply the other equation by 3.

If she adds the two equations she would be left with the variable 'x'.

Step-by-step explanation:

Given the two equations are as follows:

$ 2x - 3y = 12 \hspace{5mm} \hdots (1) $

$ 5x + 6y = 18 \hspace{5mm} \hdots (2) $

It is given that she multiplies the first equation by 6. Therefore, (1) becomes

$ 12x - 18y = 72 \hspace{15mm} \hdots (a) $

Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.

The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.

Therefore, Equation (2) becomes:

$ 15x + 18y = 54 \hspace{5mm} \hdots (b) $

Now, we add Equation (a) and Equation (b).

$ \implies 12x - 18y + 15x + 18y = 72 + 54 $

$ \implies 27x = 126 $

Factor: 3

Equation: 27x = 126

7 0
2 years ago
In a rational function, is the horizontal shift represented by the vertical asymptote?
ziro4ka [17]
<h3>Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>

A bit of further explanation:

The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.

Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h

For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.

7 0
2 years ago
An equation parallel and perpendicular to 4x+5y=19
UNO [17]

Answer:

Parallel line:

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

y=\frac{5}{4}x-\frac{1}{2}

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

4x+5y=19

we can change it into y=mx+b form

5y=-4x+19

y=-\frac{4}{5}x+\frac{19}{5}

so,

m=-\frac{4}{5}

Parallel line:

we know that slope of two parallel lines are always same

so,

m'=-\frac{4}{5}

Let's assume parallel line passes through (1,1)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-1=-\frac{4}{5}(x-1)

now, we can solve for y

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

m'=\frac{5}{4}

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-2=\frac{5}{4}(x-2)

now, we can solve for y

y=\frac{5}{4}x-\frac{1}{2}


4 0
3 years ago
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