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aleksandrvk [35]
3 years ago
13

What is the slope of a line that is perpendicular to the line represented by the equation x-y=8

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0
Rewrite the equation into the general form: y=mx+b, where m represents slope.
We have:
x-y=8
-y=-x+8
y=x-8
Here, m happens to be 1. The slope of a perpendicular line to an equation is the negative reciprocal of the number. 
For example, the negative reciprocal of 2 is -1/2 (so you 'flip' the number).
So the negative reciprocal of 1, or 1/1, is -1.
So the slope of the line perpendicular to that equation is -1.
Paraphin [41]3 years ago
5 0
Slope of line is -1 , i think
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For this case we have the following definitions:


A function is even if, for each x in the domain of f, f (- x) = f (x). The even functions have reflective symmetry through the y-axis.


A function is odd if, for each x in the domain of f, f (- x) = - f (x). The odd functions have rotational symmetry of 180º with respect to the origin.


We then have the following function:

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