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dsp73
3 years ago
5

Write three numbers that could fit between 6.21 and 6.22.

Mathematics
1 answer:
Ad libitum [116K]3 years ago
5 0

Answer: 6.211, 6.111, and 6.21 are all possible answers.

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The resting heart rates for a sample of individuals are normally distributed with a mean of 70 and a standard deviation of 15. U
Liono4ka [1.6K]

Answer:

84%

Step-by-step explanation:

The empirical rule states that 68% values are within 1 standard deviation of mean, i.e,

70

±

15

or from 55 to 85. Since normal distribution is symmetric, we must have (32%) outside this range, and 32/2=16% on the right if this range. Hence below 85 we have (100-16) % = 84%

7 0
3 years ago
It cost Louis five dollars to park his car at a parking meter for two hours what is the price to park for one hour job bar model
SashulF [63]
2.5 dollars (I think) or 2.50
4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP WILL GIVE BRAINLIEST!!!!
max2010maxim [7]

Answer:

Step-by-step explanation:

y intercept is -6

the slope is already in it's fraction form but if you want it back to whole number it's y=1.33x-6

the slope is positive

Some plots you can put are (6, 2) and (12, 10)

Just start at (0, -6) and counts 4 up and 3 right

4 0
3 years ago
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

W \approx 1.77*10^{35}}J

5 0
3 years ago
Please help and show steps so i could figure out how to do it , will give branliest!
erastova [34]

Answer:

8

Step-by-step explanation:

1. 3b - 2 (1 - b) / a - 2

2. 3(2) - 2 (1 - 2) / 3 - 2

3. 6 - 2 (-1) / 1

4. 6 + 2 / 1

5. 8 / 1

6. 8

3 0
3 years ago
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