Answer:
1. At the end of S phase- 20 pg DNA
2. At the end of G2 phase- 20 Pg DNA
Explanation:
The cell before undergoing M phase undergoes the steps of interphase that is G₁, S and G₂ phase.
During S phase, the process of cell replication takes place which replicates the DNA as a result of which the amount of DNA doubles. This DNA amount is reduced to half during the anaphase stage of M phase.
In the question since the amount of DNA is 10pg therefore the amount will be double during S phase and becomes 20 pg and will remain 20 pg until the DNA is distributed therefore at the end of G₂ phase Will remain the 20 pg.
There are many steps for that and here I'm going to explain it to you. The first step is that a cell copies the genetic instructions and then the dna unrolls. The second step is that RNA polymerase binds onto the strand. Then the third step is that the messenger RNA is ordered to go out of the nucleus into the cytoplasm to a ribosome. ANd the final step is the the ribosomes <span>then take the mRNA and translate it into amino acids. That is how it is translated</span>
Answer:
Deserts, Beaches and other sandy environments :)
Explanation:
Answer:
Oxidative Phosphorylation in glycolysis.
Explanation:
Kinases are the enzymes which cause transfer of the phosphate group from one molecule to another molecule . As the PEP is converted to pyruvate in glycolysis by a pyruvate kinase enzyme it causes phosphorylation. It is one of the important regulatory steps of glycolysis.
