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inessss [21]
3 years ago
8

you get a free meal at his favorite restaurant having to spend $50 or more at the restaurant he already spent $30.25. how much m

ore does tom need to send to get his free meal?
Mathematics
1 answer:
jeyben [28]3 years ago
6 0
Subtract $30.25 from $50
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The area of the rectangle shown is 44 m2.<br> | 3 m<br> x m<br> Work out the missing length x.
andrew11 [14]

Answer:

area = length \times width \\ 44 = 3 \times x \\ x =  \frac{44}{3}

8 0
3 years ago
What value of x is in the solution set of 4x – 12 ≤ 16 + 8x?
gtnhenbr [62]
The solution for the x-value in this set is -7≤x
4 0
4 years ago
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Maths people please write the answers !<br><br><br> Equations- Maths
Korvikt [17]

Answer:

length = 20cm

breadth = 8cm

Step-by-step explanation:

solution;

length(l) = x + 12

breadth(b) = x

perimeter (p) = 56 cm

we know that,

perimeter(p) = 2(l + b)

or, 56 = 2(x + 12 + x)

or, 56 = 2(2x + 12)

or, 56 = 4x +24

or, 56 - 24 = 4x

or, 32 = 4x

or, 32 / 4 = x

x = 8

now

putting the value of x in length and breadth

length = x+ 12

=8 + 12

=20cm

breadth = 8cm

7 0
3 years ago
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(40/5)-7+2? I know the answer but I don’t know how I got to it
ExtremeBDS [4]

Answer:

3

Step-by-step explanation:

(40/5)-7+2

PEMDAS says parentheses first, so divide inside the parentheses

(8)-7+2

Then add and subtract from left to right

1 +2

3

8 0
3 years ago
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A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells.
Sergio039 [100]

Answer:

This mileage interval is from 30120 miles and higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

All he knows is that, for a large number of tires tested, the mean mileage was 25,000 miles, and the standard deviation was 4000 miles. This means that \mu = 25000, \sigma = 4000.

A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells. What interval wouldyou suggest?

The lower end of this interval is X when Z has a pvalue of 0.90.  That is Z = 1.28.

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 25000}{4000}

X - 25000 = 4000*1.28

X = 30120

This mileage interval is from 30120 miles and higher.

7 0
3 years ago
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