Triangle LKJ is similar to triangle TSR. Which of the following statements is true?

Mathematics

1 answer:

mars1129 [50]2 years ago

6 0

Answer:

the 3rd choice is correct

Step-by-step explanation:

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Answer: the answer is d

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2 years ago

Write an equation that represents the following statement. Five less than the product of r and two is 3.

liraira [26]

Your equation should be 5 - r + 2 = 3.

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2 years ago

Pls help me it's due today

Dimas [21]

Answer:

r³ + 15r² - 10r - 4

Step-by-step explanation:

First, note you can remove the brackets, in this case they contribute nothing at all.

Then, group the like terms and add them, e.g., we have 3r³ and -2r², they add up to r³.

Finally, order them from greatest power of r to smallest power of r.

That's all!

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3 years ago

What is another example for data on a statistical question

svet-max [94.6K]

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Step-by-step explanation:

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2 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

3 0

3 years ago