In rhombus ABCD, AB=14 and AC=19. Find the area of the rhombus to the nearest tenth. A 190.7 B 228.3 C 195.4 D 179.8
1 answer:
Answer:
C
Step-by-step explanation:
The triangle ABC has two sides that are 14 and 1 side that is 19. We can use Heron's formula to Calculate ABC.
s = (a + b + c)/2
s = (14 + 14 + 19)/2 = 23.5
s - a = 23.5 - 14 = 9.5
s - b = 23.5 - 14 = 9.5
s - c = 23.5 - 19 = 4.5
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Area = sqrt(s * (s - a) * (s - b) * (s - c) )
Area = sqrt(23.5 * 9.5 * 9.5 * 4.5)
Area = sqrt(9543,9)
Area = 97.69
But ABC is only 1/2 the rhombus. The area is twice that amount.
Area = 2 * 97.69 = 195.4
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Step-by-step explanation:
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Hope this helps.
Hello!
So let's first start out by solving the left side of the equation:
2 to the third power is 8
The right side now: -3 to the second power is -9
In total: 8- (-9)
So your answer is C) -1
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Answer:
Hold on a sec i cant remember
Answer:
672
Step-by-step explanation:
Formula is length times width times height
14 x 8 = 112
112 x 6 = 672
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