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melisa1 [442]
4 years ago
9

How do you solve: 3 (x-1)=6

Mathematics
2 answers:
SVETLANKA909090 [29]4 years ago
8 0
If you're trying to find x first expand the brackets by multiplying whats on the outside; 3 by everything inside the bracket giving you 3x-3=6 then balance it by adding 3 to one side and doing the same on the other side to get 3x=9 then divide by 3 on both sides to give you an answer of x=3 hope that helps ^^; 
Leni [432]4 years ago
3 0
Multiply 3 times x which gives you 3x then multiply 3 times -1 which gives you -3. Now you have an equation 3x-3=6. This is a two step equation so you have to add 3 (inverse operation) to 6 which gives you 9. Now you divide 9/3 which equals 3. The answer is 3
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Which statement BEST describes the growth of bacteria modeled by the function f(x)=1.8x
lara [203]

Answer:


Step-by-step explanation:

f(x) = 1.8x is a linear function and does not model the growth of bacteria.  Perhaps you meant f(x) = 1.8^x, which is an exponential function whose initial value is 1.  Please ensure that you have copied down this problem exactly as it was presented.



6 0
3 years ago
HELP PLEASE YOU'LL GET 25 POINTS
ollegr [7]

Answer:

50

Step-by-step explanation:

Im pretty sure

5 0
3 years ago
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Maria needs to buy 12 wine glasses. write an expression of the cost of 12 glasses at p dollars each.
irinina [24]

12p thats it because you are buying 12 glasses a the cost of p example 12 glasses for 5 dollars would be 12(5)=60

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4 years ago
How to find left and right inverse of a 3x2 matrix.
Mnenie [13.5K]

Let A be a 3×2 matrix, L its left inverse, and R its right inverse. L and R are then matrices such that LA = I₂ (the 2×2 identity matrix) and AR = I₃ (the 3×3 identity matrix). Clearly L must be 2×3 and R must be 3×2 in order for the matrix products to be defined.

To find L and R, we start by introducing a square matrix on the the left sides of either equation above. In particular, we uniformly multiply both sides by the transpose of A, then solve for the inverse.

For the left inverse, we have

LA=I

(LA)A^\top = IA^\top

L\left(AA^\top\right) = A^\top

\left(L\left(AA^\top\right)\right)\left(AA^\top\right)^{-1} = A^\top \left(AA^\top\right)^{-1}

L\left(\left(AA^\top\right)\left(AA^\top\right)^{-1}\right) = A^\top \left(AA^\top\right)^{-1}

LI = A^\top \left(AA^\top\right)^{-1}

L = A^\top \left(AA^\top\right)^{-1}

We do the same thing for the right inverse, but take care with how we multiply both sides of AR = I₃.

AR=I

A^\top(AR)=A^\top I

\left(A^\top A\right)R = A^\top

\left(A^\top A\right)^{-1} \left(\left(A^\top A\right)R\right) = \left(A^\top A\right)^{-1} A^\top

\left(\left(A^\top A\right)^{-1} \left(A^\top A\right)\right) R = \left(A^\top A\right)^{-1} A^\top

IR = \left(A^\top A\right)^{-1} A^\top

R = \left(A^\top A\right)^{-1} A^\top

4 0
3 years ago
A group of 180 students is divided into 20 teams for a competition. b. Part way through the competition, the students are gather
frosja888 [35]

Step-by-step explanation:

180 + 20 + 5 suma eso y la respuesta está correcta

7 0
2 years ago
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