3 years ago

(2yx^2+2yx–3a^2)(y^2x^2)

1 answer:

5 0

(2yx^2+2yx-3a^2)(y^2x^2)
= (2yx^2)(y^2*x^2)=(2yx(Y^2*x^2)+(-3a^2)(y^2*x^2)
=2x^4*y^3+2x^3*y^3-3a^2*x^2*y^2
=2x^4*y^3-3a^2*^2*y^2+2x^3*y^3

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