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hjlf
3 years ago
15

(2yx^2+2yx–3a^2)(y^2x^2)

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0
(2yx^2+2yx-3a^2)(y^2x^2)
= (2yx^2)(y^2*x^2)=(2yx(Y^2*x^2)+(-3a^2)(y^2*x^2)
=2x^4*y^3+2x^3*y^3-3a^2*x^2*y^2
=2x^4*y^3-3a^2*^2*y^2+2x^3*y^3
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Enter the value of h(-4) for h(x)=(x-2)2+3x in the box.
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Step-by-step explanation:

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7 0
2 years ago
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Bacteria vary somewhat in size, but a diameter of 1.5 μ m is not unusual.
Dmitrij [34]

Answer:

a) 1.8 × 10^-12 cm³ or 1.8 × 10^-12 cubic meters

b) 7.1 × 10^-6 mm² or 7.1 × 10^-6 square millimeters

Step-by-step explanation:

a) We are assuming that the shape of the bacteria is a sphere.

Hence, Volume of the Sphere(Bacteria) = 4/3 × π × r³

Diameter = 1.5 μm

Radius = Diameter/2 = 1.5μm/2

= 0.75μm

We are told that the volume should be in cubic centimeters

Converting 0.75μm to centimeters

1 μm = 1 × 10^-4 cm

0.75 μm =

Cross Multiply

= 0.75 μm × 1 × 10^-4 cm/ 1 μm

= 0.000075cm

Volume of the Sphere(Bacteria) = 4/3 × π × r³

= 4/3 × π × (0.000075)³

= 1.767145867 × 10^-12 cm³

Approximately as 2 significant figures = 1.8 × 10^-12 cm³

b) The formula for the Surface area of a Sphere = 4πr²

Diameter = 1.5 μm

Radius = Diameter/2 = 1.5μm/2

= 0.75μm

We are told that the surface area should be in square millimeters

Converting 0.75μm to millimeters

1 μm = 0.001 mm

0.75 μm =

Cross Multiply

= 0.75 μm ×0.001mm/ 1 μm

= 0.00075mm

Surface Area of a Sphere

= 4 × π × r²

= 4 × π × 0.00075²

= 7.06858 ×10^-6 mm²

Approximately to 2 significant figures

= 7.1 × 10^-6 mm²

6 0
3 years ago
One large bubble separates into four small bubbles so that the total area of the small bubbles is equal to the area of the large
anzhelika [568]

Answer:

10 cm.

Step-by-step explanation:

We'll begin by calculating the area of the small bubble. This can be obtained as follow:

Radius (r) = 5 cm

Area (A) =?

Since the bubble is circular in nature, we shall use the formula for area of circle to determine the area of the bubble. This is illustrated below:

A = πr²

A = π × 5²

A = 25π cm²

Next, we shall determine the total area of the small bubbles. This can be obtained as follow:

Area of 1 bubble = 25π cm²

Therefore,

Area of 4 bubbles = 4 × 25π cm²

Area of 4 bubbles = 100π cm²

Finally, we shall determine the radius of the large bubble. This can be obtained as follow:

Area of large bubble = total area of small bubbles = 100π cm²

Radius (r) =?

A = πr²

100π = πr²

100 = r²

Take the square root of both side

r = √100

r = 10 cm

Thus, the radius of the large bubble is 10 cm

5 0
2 years ago
Answers? Thanks so much in advance for any help :)
LuckyWell [14K]
13. AC=6 

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3 years ago
write two different inequalities in which one of the solutions is the same as the solution to x - 23 = 192
Slav-nsk [51]

Answer:

I don't no the answer sorry

3 0
3 years ago
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