(2yx^2+2yx–3a^2)(y^2x^2)

1 answer:

5 0

(2yx^2+2yx-3a^2)(y^2x^2)
= (2yx^2)(y^2*x^2)=(2yx(Y^2*x^2)+(-3a^2)(y^2*x^2)
=2x^4*y^3+2x^3*y^3-3a^2*x^2*y^2
=2x^4*y^3-3a^2*^2*y^2+2x^3*y^3

You might be interested in

Jason has 65 t-shirts and wants to give away 15% of them to help make room in his closet.

DiKsa [7]

Answer:

Step-by-step explanation:

i'm not really sure but i'm sure it's accurate

5 0

3 years ago

Read 2 more answers

KA- correct answers only, thanks!

strojnjashka [21]

Answer:

Step-by-step explanation:

The constant of proportionality is 2/3 bc it lands on 2/3 and 4/6 simplified is 2/3 as well :)

3 0

2 years ago

Find the remainder when 3x^3+ 6x-1 is divided by x-3

Sauron [17]

Answer:

Step-by-step explanation:

by remainder theorem p(3) is the remainder

and therefore it is 93

3 0

3 years ago

executive committee consists of 15 members: 7 men and 8 women. 5 members are selected at random to attend a meeting in Hawaii.

larisa [96]

Answer:

1over3

Step-by-step explanation:

number of successful outs come over the total number 5over 15

7 0

3 years ago

ANYONE??

RideAnS [48]

Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height

b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²

Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²

data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft

(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.

Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³

Answer: ≈202.3 ft³

5 0

3 years ago