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Marat540 [252]
3 years ago
13

What is x^3−x^2−x+1 divided by x^2−2x+1 ?

Mathematics
2 answers:
Mars2501 [29]3 years ago
7 0

 

\displaystyle\bf\\x^3-x^2-x+1 = \\\\=x^2(x - 1) - (x - 1)= \\\\=(x - 1)(x^2 - 1) =\\\\= (x - 1)(x - 1)(x + 1) = \\\\=(x - 1)^2(x + 1) = \\\\(x^2 - 2x + 1)(x + 1)\\\cdots\cdots\cdots\cdots\cdots\cdots\cdots\cdots\\(x^2 - 2x + 1)(x + 1)~\vdots~(x^2 - 2x + 1)\\\\\implies~~x^3-x^2-x+1~~\text{ is divisible by }~~ x^2-2x+1 \\\\Verify:\\\\\frac{x^3-x^2-x+1}{x^2-2x+1}=\frac{(x^2 - 2x + 1)(x + 1)}{x^2-2x+1}=x+1



shutvik [7]3 years ago
5 0
X^3-x^2-x+1 divided by x^2-2x+1 equals x + 1
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