Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
25 percent increase 24 *1.25 =30
Answer:
Monday if you are talking about a Single days lost but in whole Wednesday could be the answer if they include all down days 8n the week. hopes this helps
Answer:
y = 4/3x - 4
Step-by-step explanation:
to find the equation of a line with 2 points, we use the slope formula which is:
we will use (6,4) as ![x_1[tex] and [tex]y_1](https://tex.z-dn.net/?f=x_1%5Btex%5D%20and%20%5Btex%5Dy_1)
and we will use (-3,-8) as ![x_2[tex] and [tex]y_2](https://tex.z-dn.net/?f=x_2%5Btex%5D%20and%20%5Btex%5Dy_2)
. we plug this into the slope formula:
-8 - 4 = -12
-3 - 6 = -9
the slope is 
but we can simplify this further by dividing the fraction by -3
-12 / -3 = 4
-9 / -3 = 3
the simplified version of the slope is 
we can write this in slope-intercept form which is y =mx + b, with b being the y intercept and m being the slope
y = 4/3x + b <--- we need to solve for <em>b</em> in order to find the y intercept, so substitute x & y for a point on the line, we can use any point we are given, but for this example i will use (6,4)
4 = 4/3(6) + b < multiply 4/3 x 6
4 = 8 + b < subtract 8 from both sides
-4 = b
our y intercept would be (0,-4)
the equation looks like the following:
y = 4/3x - 4, which is our answer
The Area of the platform is 33m²
Step-by-step explanation:
As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m
Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m
Since the platform is five-sided, the figure can be broken down into constituting parts
- Parallelogram ║ABCE
- Δ DCE
Are of the figure= Area of ║ABCE+ area Δ DCE
Area of ║ABCE= breadth * height
= 6*4 ⇒24m
²
Area Δ DCE= ½*(base)(height)
Putting the value of base is 6m and height as 3m
Area Δ DCE= ½*6*3
=9m
²
Total area= 24+9= 33m
²
