Answer:
Use the formula y-y1=m(x-x1) <---memorize this. The m here is the slope.
Step-by-step explanation:
The equation is in y=mx+b form
Remember mx=slope and b=y-intercept
The question wants you to find the equation that is Parallel to y=-3x-2 and passes through (-3,-3)=(x1,y1)
Parallel=same slope -3x
So now all that's left is to plug into the equation.
y-(-3)=-3(x-(-3))
y+3=-3(x+3) ----> positive - a negative = positive so x-(-x)=x+x
y+3=-3x-9 ----> distribute like terms(subtract 3 from 3 and 3 from -9)
y=-3x-12 - This is your answer, you can check by graphing it.
Could i get Brainlest? thx :)
Your points are (-2, 7) and (18, 1). To find the slope, use the slope formula (y_2 - y_1)/(x_2 - x_1)
(18, 1) --> (x_2, y_2)
(-2, 7) --> (x_1, y_1)
(1 - 7)/(18 - (-2)) --> -6/20 --> -3/10
The slope of the line passing through the points (-2, 7) and (18, 1) is -3/10.
Step-by-step explanation:
find the Lcm of 15 and 10 which is 30
multiply the 2fractions by the LCM
8/15*30=16
3/10*30=9
add the products and put them all over the Lcm
(16+9)/30
=25/30 which is equivalent to 5/6 when you divide both the numerator and the denominator by 5
