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kramer
3 years ago
13

What’s the value of x ?

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0
The answer is 29
Here’s my work:

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NEED THE ANSWERS FOR THIS ASAP, SOMEONE PLEASE HELP ME !!
photoshop1234 [79]

Answer:

1. 1/1 , 1, 100%

2. 1/2, 0.5, 50%

3. 1/3, 0.3, 30%

4. 2/3, 0.6, 60%

5. 1/4, 0.25, 25%

6. 3/4, 0.75, 75%

7. 1/5, 0.2, 20%

8. 2/5, 0.4, 40%

9. 3/5, 0.6, 60%

10. 4/5, 0.8, 80%

11. 1/6, 0.16, 16%

12. 5/6, 0.83, 83%

13. 1/8, 0.125, 12.5%

14. 3/8, 0.375, 37.5%

15. 5/8, 0.625, 62.5%

16. 7/8, 0.875, 87.5%

3 0
3 years ago
I need help very much please
musickatia [10]

Answer:

1/4

Step-by-step explanation:

5/20 = 1/4

hope this helps

4 0
3 years ago
Read 2 more answers
Val walks 2 3/5 miles each day . Bill returns 10 miles once every 4 days . In 4 days, who covers the greatest distance
julia-pushkina [17]
Val by 4/10 walk longer
7 0
3 years ago
Help me please,Thanks
maxonik [38]
<span>Anna learns in her science class that the human eye blinks an average of 4,200,000 times a year. What is this number expressed in scientific notation?</span>
6 0
3 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
3 years ago
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