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EastWind [94]
3 years ago
6

How might you prove your observations about the slope of a midsegment in part d using algebra and x- and y-coordinates? Briefly

outline an approach using what you know about midpoints and parallel lines. Use the figure you created in GeoGebra to guide you.
Mathematics
2 answers:
ioda3 years ago
4 0

Answer: I can use variables to represent the coordinates of the vertices for a general triangle ABC. then I can calculate the midpoints of the sides in terms of the same variables, and calculate the slope of each midsegment showing that the expression for the slope of a midsegment is the same as the expression for the slope of the third side of the triangle proves that the two are parallel.

Step-by-step explanation: this is word for word btw!

Lesechka [4]3 years ago
3 0

Answer:

Answer: I can use variables to represent the coordinates of the vertices for a general triangle ABC. then I can calculate the midpoints of the sides in terms of the same variables, and calculate the slope of each midsegment showing that the expression for the slope of a midsegment is the same as the expression for the slope of the third side of the triangle proves that the two are parallel.

Step-by-step explanation: this is word for word btw!

Step-by-step explanation:

THANKS U PLATO

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3 years ago
Exercise 1.A committee of five people is chosen randomly from four men and six women. Find the probability that:a) Exactly four
MatroZZZ [7]

Answer with explanation:

Given : Number of men = 4

Number of women = 6

Total people = 6+4=10

Total number of ways to make a committee of five people from 10 persons :-

^{10}C_{4}=\dfrac{10!}{4!(10-4)!}=210

a) Number of ways to make committee that has exactly four women :

^6C_4\times ^4C_1=\dfrac{6!}{4!(6-4)!}\times4=60

The  probability that committee has exactly four women :

\dfrac{60}{210}=\dfrac{2}{7}

b) Number of ways to make committee that has at-least four women :

^6C_4\times ^4C_1+^6C_5=\dfrac{6!}{4!(6-4)!}\times4+6=66

The probability that committee at-least four women :

\dfrac{66}{210}=\dfrac{22}{70}

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\dfrac{6}{210}

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3 years ago
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