Answer:
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Step-by-step explanation:
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Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Using the interpretation of a confidence interval, it is found that approximately 950 of those confidence intervals will contain the value of the unknown parameter.
A x% confidence interval means that we are x% confident that the population mean is in the interval.
- Out of a large number of intervals, approximately x% will contain the value of the unknown parameter.
In this problem:
- 95% confidence interval.
- 1000 samples.
0.95 x 1000 = 950
Hence, approximately 950 of those confidence intervals will contain the value of the unknown parameter.
A similar problem is given at brainly.com/question/24303674
