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Hunter-Best [27]
3 years ago
6

What is = to 5/10? With the denomnator of 6?

Mathematics
1 answer:
IrinaK [193]3 years ago
8 0
The answer in 5/10= 3/6
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The radio is of a circle is 3 millimeters what is the circles circumference
nlexa [21]

c = 2(3.14)(radius)

c = 2(3.14)(3)

<em>multiply all those numbers together to get your circumference.</em>

c = 18.84.

6 0
3 years ago
A rectangular prism with a volume of 5 cubic units is filled with cubes with side lengths of 1/3
pishuonlain [190]

Step-by-step explanation:The volume of each cube = (side)^3 = (1/3)^3 = 1/27 cubic units

The number of cubes that will fill the prism =

Vol of prism 4

__________ = _____ = 4 * 27 = 108 cubes

Vol of cube (1/27)

5 0
3 years ago
Read 2 more answers
Exponential growth/decay problem 1
RUDIKE [14]

Answer:

a) growth

b) $500

c) 6% = 0.06

d) f(x)=500(1.06)^x

e) $595.51

Step-by-step explanation:

<u />

<u>Part (a)</u>

Exponential GROWTH, since interest is applied to the account each year.

<u>Part (b)</u>

Initial amount = $500

<u>Part (c)</u>

Growth factor = 6% = 0.06 (in decimal form)

<u>Part (d)</u>

General form of exponential growth function:

f(x)=a(1+r)^x

where:

  • a = initial amount
  • r = rate of growth (in decimal form)
  • x = time (in years)

Given:

  • a = 500
  • r = 0.06

\implies f(x)=500(1+0.06)^x

\implies f(x)=500(1.06)^x

<u>Part (e)</u>

when x = 3

\begin{aligned}\implies f(3) & =500(1.06)^3\\ & = 595.51\: \sf(nearest\:hundredth)\end{aligned}

5 0
2 years ago
Kate has 2.95 in quarter and nickels she has 23 coins how many quarters and nickles does she have
cluponka [151]
Kate has 11 quarters and 4 nickels
8 0
2 years ago
Read 2 more answers
Given the piecewise function above evaluate the following statements. (write "DNE" if the limit does not exist)
Sveta_85 [38]

By analyzing the graph of the function, we will see that:

  • a) DNE
  • b) 3
  • c) -1
  • d) 3
  • e) DNE
  • f) 2

<h3>How to get the limits of the given function?</h3>

Remember that when we take a limit to a given value, we approach to that value by two directions (from above and below) and see at which value the function approaches.

So, for the first limit we have:

x ⇒ -2

As you can see, if we approach from below the function tends to 4, while if we approach from above, the function tends to -1, which means that this limit does not exist. DNE.

x ⇒ 0

The function is continuous here, so the limit is equal to the value of the function in that point, which is 3

x ⇒ 2

If we approach from above and below we get the same number, which is -1, so the limit is equal to -1.

x = 2

Now we are directly evaluating the function in x = 2, and we can see that there is a jump such that f(2) = 3

x ⇒ 4

Here we have two asymptotes, one goes to infinity and the other to negative infinity, so this limit does not exist.

x ⇒ ∞

So we can't see how the function behaves for large values of x, so there is no way to answer this exactly.

If we suppose that the function does not change, we can see that we have a rational function in the right side of the image, so we can expect that as x tends to infinity, the function will tend asymptotically to 2.

Why 2?

Because the denominator becomes zero when x = 4, then when x = 5 the denominator is equal to 1.

At that point, the function is equal to 3, so the function is something like:

y = 1/(x - 4) + 2

If you want to learn more about limits, you can read:

brainly.com/question/5313449

5 0
2 years ago
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