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2 years ago

Name the value of each 2in 222,222

Mathematics

1 answer:

mixas84 [53]2 years ago

6 0

Ones,tenths,hundreths, thousands,tenthousands,hundredthousands

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( 3x + 5 ) ki power 2 expend it

Pepsi [2]

This question is soooo easy

Step-by-step explanation:

(3x)^2+(5)^2+2.3x.5

9x^2+25+30x

4 0

2 years ago

Which of the following are solutions to the equation below (5x+1)^2=7? Check all that apply.

stiv31 [10]

(5x+1)² = 7; expand: 25x² + 10x +1 = 7 or 25x² + 10x -6 = 0

Solve this quadratic for x:

x = [-b + √(b² - 4ac)]/2a and x = [-b - √(b² - 4ac)]/2a
Plug the values and you'll find :
x = (- √7 - 1)/5 (answer C)
x = (+√7 -1)/5 (answer E)

4 0

2 years ago

Read 2 more answers

What is 578 x 6,937, please

kati45 [8]

400,958,6 Hope this helps!

7 0

3 years ago

Read 2 more answers

Which number line shows the solution to 1/4 X + 1 < 5

alex41 [277]

Answer:

I think it's the third one

Step-by-step explanation:

I've done this before, but try the 3rd one, if not then try the second one. it's been awhile since I've done this. I'm sorry if I'm wrong

5 0

3 years ago

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

5 0

2 years ago