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3 years ago

Write an algebraic expression for the words: "10 less than p".

Mathematics

2 answers:

poizon [28]3 years ago

7 0

"10 is less than P"
The algebraic expression for that would be:
10

(Hope this helps!)

olga55 [171]3 years ago

4 0

10 less than p:

10<p

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What is the relationship between the 5s in the number 755,371

Gennadij [26K]

The value of 5 in the ten-thousands place is 10 times greater than the value of 5 in the thousands place.
You can also say that the value of 5 in the thousands place is 10 times less than the value of 5 in the ten-thousands place.

4 0

3 years ago

A study was conducted to measure the effectiveness of hypnotism in reducing pain. The measurements are centimeters on a pain sca

blondinia [14]

The confidence interval for mean of the "before-after" differences is $\fbox{(-0.4037,1.8037)}$

Further explanation:

Find the difference between the before pain and the after pain.

Difference = before-after

Kindly refer to the Table for the difference of between the before and after pain.

Sum of difference = $5.6$

Total number of observation = $8$

Mean of difference = $0.7$

Sample standard deviation $s$ = $1.3201$

Level of significance = $5\%$

Formula for confidence interval = $\left( \bar{X} \pm t_{n-1, \frac{\alpha}{2}\%} \frac{s}{\sqrt{n}} \right)$

confidence interval = $\left( 0.7 \pm t_{8-1, \frac{5}{2}\%} \frac{1.3201}{\sqrt{8}} \right)$

confidence interval = $\left( 0.7 \pm t_{7, \frac{5}{2}\%} \frac{1.3201}{\sqrt{8}} \right)$

From the t-table.

The value of $t_{7, \frac{5}{2}\%$ = $2.365$

Confidence interval = $( 0.7 \pm 2.365}\times \frac{1.3201}{\sqrt{8}}) \right)$

Confidence interval = $\left( 0.7 - 2.365}\times \0.4667,0.7 + 2.365}\times \0.4667) \right$

Confidence interval = $(0.7-1.1037,0.7+1.1037)$

Confidence interval = $\fbox{(-0.4037,1.8037)}$

The $95\%$ confidence interval tells us about that $95\%$ chances of the true mean or population mean lies in the interval.

Yes, the hypnotism appear to be effective in reducing pain as confidence interval include includes the positive deviation from the mean.

Learn More:

1. Learn more about equation of circle brainly.com/question/1506955

2. Learn more about line segments brainly.com/question/909890

Answer Details:

Grade: College Statistics

Subject: Mathematics

Chapter: Confidence Interval

Keywords:

Probability, Statistics, Speed dating, Females rating, Confidence interval, t-test, Level of significance , Normal distribution, Central Limit Theorem, t-table, Population mean, Sample mean, Standard deviation, Symmetric, Variance.

7 0

3 years ago

Read 2 more answers

There are three numbers. The first number is twice the second number. The third number is twice the first number. The sum of the

mel-nik [20]

Answer:

x = 32 y = 16 z = 64

Step-by-step explanation:

x is the 1st number

y is the 2nd number

z is the 3rd number

The first number is twice the second number so

x = 2 y

The third number is twice the first number.

z = 2 x

Their sum is 112

x + y + z = 112

Plus in what we know:

x + y + z = 112

2 y + y + 2x = 112

3y + 2x = 112 Let's solve for y and subtract 2x from each side

3y = 112 - 2x Divide both sides by 3

y = $\frac{112 - 2x}{3}$

Now plug our answer back in to solve for x.

x = 2y

x = 2 ( $\frac{112 - 2x}{3}$ )

x = (224 - 4x) / 3 Multiply each side by 3.

3x = 224 - 4x Add 4x to each side

3x + 4x = 224

7x = 224 Divide each side by 7

7x / 7 = 224 / 7

x = 32

Now we can solve for z.

z = 2x

z = 2 ( 32 )

z = 64

Now we can solve for the numerical value of y.

x + y + z = 112

32 + y + 64 = 112

96 + y = 112 Subtract 96 from each side.

y = 112 - 96

y = 16

5 0

3 years ago

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What's is the slope intercept equation of the line below

baherus [9]

Answer:

y = -1 - 2/1x

Step-by-step explanation:

Glad to help! :)

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2 years ago

Identify the value of m. Give your answers in simplest radical form. HELP PLEASE!!!

yan [13]

Answer:

m = 4√2

Step-by-step explanation:

This is a right angled isosceles triangle whose sides are in the ratio 1:1:√2.

So = 8 / √2

= 8 *√2 / 2

= 4√2

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3 years ago