All categories

3 years ago

Write an algebraic expression for the words: "10 less than p".

Mathematics

2 answers:

poizon [28]3 years ago

7 0

"10 is less than P"
The algebraic expression for that would be:
10

(Hope this helps!)

olga55 [171]3 years ago

4 0

10 less than p:

10<p

You might be interested in

Helpppp pleaseeeee summer school needs done

lidiya [134]

I’m not to sureee my baddd

5 0

3 years ago

A flagpole is 20 feet tall. At 4 p.m. it casts a shadow that is 15 feet long. How far is it from the top of the flagpole to the

evablogger [386]

9514 1404 393

Answer:

25 feet

Step-by-step explanation:

The hypotenuse of the right triangle with legs 15 feet and 20 feet can be found using the Pythagorean theorem:

h^2 = 20^2 +15^2

h^2 = 400 +225 = 625

h = √625 = 25

The distance from the shadow tip to the flag pole tip is 25 feet.

3 0

3 years ago

B. Convert quarts to gallons.

jeyben [28]

Answer:

There are 4 quarts in one gallon. 36 divided by 4 is 9 gallons.

Step-by-step explanation:

9 gallons.

5 0

3 years ago

Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to

polet [3.4K]

Answer:

(a) The probability that X is at most 30 is 0.9726.

(b) The probability that X is less than 30 is 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is 0.7406.

Step-by-step explanation:

We are given that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked. A random sample of 200 shafts is taken.

Let X = the number among these that are nonconforming and can be reworked

The above situation can be represented through binomial distribution such that X ~ Binom(n = 200, p = 0.11).

Here the probability of success is 11% that this much % of all steel shafts produced by a certain process are nonconforming but can be reworked.

Now, here to calculate the probability we will use normal approximation because the sample size if very large(i.e. greater than 30).

So, the new mean of X, $\mu$ = $n \times p$ = $200 \times 0.11$ = 22

and the new standard deviation of X, $\sigma$ = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{200 \times 0.11 \times (1-0.11)}$

= 4.42

So, X ~ Normal( $\mu =22, \sigma^{2} = 4.42^{2}$ )

(a) The probability that X is at most 30 is given by = P(X < 30.5) {using continuity correction}

P(X < 30.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{30.5-22}{4.42}$ ) = P(Z < 1.92) = 0.9726

The above probability is calculated by looking at the value of x = 1.92 in the z table which has an area of 0.9726.

(b) The probability that X is less than 30 is given by = P(X $\leq$ 29.5) {using continuity correction}

P(X $\leq$ 29.5) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{29.5-22}{4.42}$ ) = P(Z $\leq$ 1.70) = 0.9554

The above probability is calculated by looking at the value of x = 1.70 in the z table which has an area of 0.9554.

(c) The probability that X is between 15 and 25 (inclusive) is given by = P(15 $\leq$ X $\leq$ 25) = P(X < 25.5) - P(X $\leq$ 14.5) {using continuity correction}

P(X < 25.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{25.5-22}{4.42}$ ) = P(Z < 0.79) = 0.7852