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bulgar [2K]
3 years ago
8

Events a, b, and c in a sample space have p(a)=0.2, p(b)=0.4, and p(c)=0.1. find p(a ∪ b ∪

Mathematics
1 answer:
Julli [10]3 years ago
3 0
If A and B are mutually independent, then \mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B) and \mathbb P(A\cap B)=0.

If A and C are independent, then \mathbb P(A\cap C)=\mathbb P(A)\cdot\mathbb P(C). Ditto for B and C.

The inclusion/exclusion principle says that

\mathbb P(A\cup B\cup C)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\mathbb P(A\cap B)-\mathbb P(A\cap C)-\mathbb P(B\cap C)+\mathbb P(A\cap B\cap C)

Since A and B are mutually exclusive, their intersection is the empty set. It then follows that A\cap B\cap C also is the empty set, so the last probability is also 0.

Plug in what we know:

\mathbb P(A\cup B\cup C)=0.2+0.4+0.1-0-0.2\cdot0.1-0.4\cdot0.1+0

\implies\mathbb P(A\cup B\cup C)=0.64
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