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2 years ago

Plssssssss help........

Mathematics

2 answers:

Vitek1552 [10]2 years ago

8 0

Your answer is -7/15

Ludmilka [50]2 years ago

7 0

the answer to ur problem will be -7/5

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Is (3,9) a solution of the system

Verdich [7]

Yes it because any function can be a solution to any certain number of different systems

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2 years ago

A 10 ft pole has a support rope that extends from the top of the pole to the ground. The rope and the ground form a 30 degree an

mr Goodwill [35]

Answer:

The length of rope is 20.0 ft . Hence, <u>option (1) </u> is correct.

Step-by-step explanation:

In the figure below AB represents pole having height 10 ft and AC represents the rope that is from the top of pole to the ground. BC represent the ground distance from base of tower to the rope.

The rope and the ground form a 30 degree angle that is the angle between BC and AC is 30°.

In right angled triangle ABC with right angle at B.

Since we have to find the length of rope that is the value of side AC.

Using trigonometric ratios

$\sin C=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin C=\frac{AB}{AC}$

Putting values,

$\sin 30^\circ} =\frac{10}{AC}$

We know, $\sin 30^\circ}=\frac{1}{2}$

$\frac{1}{2} =\frac{10}{AC}$

On solving we get,

AC= 20.0 ft

Thus, the length of rope is 20.0 ft

Hence, <u>option (1)</u> is correct.

8 0

3 years ago

Read 2 more answers

The table shows the probabilities of winning or losing when the team is playing away

Lesechka [4]

Answer:a

Step-by-step explanation:

6 0

2 years ago

PLease help i will give brainliest

mars1129 [50]

A, because 59-56= 3.

Others are distributed on a larger scale. 11-6=5 for B, 6-0=6 for C, 8-1=7 for D

6 0

2 years ago

The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area i

lorasvet [3.4K]

Answer:

The area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by $A=l w$

Derivative w.r.t 't',

$\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}$

Now, we have given

$\frac{dl}{dt}=3\ cm/s$

$l=5\ cm$

$\frac{dw}{dt}=2\ cm/s$

$w=4\ cm$

Substitute all the values,

$\frac{dA}{dt}=(4)(3)+(5)(2)$

$\frac{dA}{dt}=12+10$

$\frac{dA}{dt}=22\ cm^2/s$

Therefore, the area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

4 0

3 years ago