Question

Population Growth

Answer 1

Answer:

Step-by-step explanation:

Given that the number of a certain type of bacteria increases continuously at a rate proportional to the number present.

Initial population = 150

Hence equation for population P would be

$P(t) = 150e^{kt}$ where t = time in hours

When t=5, P = 450

Substitute to get

$3 = e^{5k}$

k=0.2197

$P(t) = 150e^{0.2197t}$ is P(t)

P will double when

$300 = 150e^{0.2197t}$

t =3.155

Between 3rd and 4th it would double

c) Yes it doubles when 3.155 hours lapsed from the start time since t in the equation is time lapsed from start time.