So, what we will do is, multiply both top and bottom, by the conjugate of the denominator, so, the denominator is 7 + 10i, so its conjugate is 7 - 10i then, let's do so.
![\bf \cfrac{-3-7i}{7+10i}\cdot \cfrac{7-10i}{7-10i}\implies \cfrac{(-3-7i)(7-10i)}{(7+10i)(7-10i)}\implies \cfrac{(-3-7i)(7-10i)}{7^2-(10i)^2} \\\\\\ \cfrac{-21+30i-49i+70i^2}{7^2-(10^2i^2)}\implies \cfrac{-21+30i-49i+70\left( \boxed{-1} \right)}{7^2-\left[10^2\left( \boxed{-1} \right)\right]} \\\\\\ \cfrac{-21+30i-49i-70}{49-(-100)}\implies \cfrac{-91-19i}{149}\implies -\cfrac{91}{149}-\cfrac{19i}{149}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B-3-7i%7D%7B7%2B10i%7D%5Ccdot%20%5Ccfrac%7B7-10i%7D%7B7-10i%7D%5Cimplies%20%5Ccfrac%7B%28-3-7i%29%287-10i%29%7D%7B%287%2B10i%29%287-10i%29%7D%5Cimplies%20%5Ccfrac%7B%28-3-7i%29%287-10i%29%7D%7B7%5E2-%2810i%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B-21%2B30i-49i%2B70i%5E2%7D%7B7%5E2-%2810%5E2i%5E2%29%7D%5Cimplies%20%5Ccfrac%7B-21%2B30i-49i%2B70%5Cleft%28%20%5Cboxed%7B-1%7D%20%5Cright%29%7D%7B7%5E2-%5Cleft%5B10%5E2%5Cleft%28%20%5Cboxed%7B-1%7D%20%5Cright%29%5Cright%5D%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B-21%2B30i-49i-70%7D%7B49-%28-100%29%7D%5Cimplies%20%5Ccfrac%7B-91-19i%7D%7B149%7D%5Cimplies%20-%5Ccfrac%7B91%7D%7B149%7D-%5Ccfrac%7B19i%7D%7B149%7D)
What is the answer to 8y-8=37-7y
1 answer:
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Answer:
0.912
Step-by-step explanation:
<em>The complete question is attached.</em>
<em />
"OR" in probability means "ADDITION". So we find the individual probabilities and "ADD" them.
P(Plan A) would be the total people for plan A (add up column of Plan A) divided by total number of people [add up all the numbers].
Looking at the table, we have:
P (Plan A) = 38/68
Now,
P(40-49 Group) can be found by adding up the row of 40-49 age group and dividing by the total. So, we have:
P(40 - 49 Group) = 24/68
Now, adding up both:
38/68 + 24/68 = 62/68 = 0.912
The actual inverse function is:
And the domain is [0, ∞).
<h3>Where is the mistake?</h3>
Remember that for a given function f(x) with a domain D and a range R.
For the inverse function, f⁻¹(x) the domain is R and the range is D.
Here, for the given function the domain is x ≥ 3 and the range is [0, ∞).
Then for the inverse function, which is:
(to check this, you must have that):
The domain will be [0, ∞) and the range x ≥ 3
If you want to learn more about inverse functions:
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