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3 years ago

Help please need it by tonight

Mathematics

1 answer:

inysia [295]3 years ago

4 0

Answer:

1) (n+5)(n-1)

2) (n-4)(n+3)

3) (v-4)(v-1)

4) (p-4)(p+2)

5)(7x-10)(x+1)

6)(7n-1)(n-9)

Step-by-step explanation:

1) Factors of -5 that add up to 4

2) Factors of --12 that add up to -1

3) Factors of 4 that add up to -5

4) Factors of -5 that add up to 4

5) 7 $x^{2}$ -3x-10

7 $x^{2}$ +7x-10x-10

7x(x+1)-10(x+1)

(7x-10)(x+1)

6)7 $n^{2}$ -64n+9

7 $n^{2}$ -63n-n+9

7n(n-9)-(n-9)

(7n-1)(n-9)

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Find the value of the expression 6x + 3xy, when x = 2 and y = 4.

damaskus [11]

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➷ Substitute in the values:

6(2) + 3(2)(4)

Now just solve:

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7 0

3 years ago

Read 2 more answers

Solve this system of linear equations. Separate the x- and y-values with a comma.

vodomira [7]

Answer:

x = $\frac{5}{2}$ , y = $\frac{5}{4}$

Step-by-step explanation:

1. Isolate for x in one of the equations:

2x = 9x - 14y

2x-9x = 9x-9x -14y

-7x = -14y

-7x/-7 = -14y/-7

x = 2y

2. Substitute 2y in for x in the second equation:

9(2y) = 40 - 14y

3. Simplify:

18y = 40 - 14y

4. Isolate for y:

18y+14y = 40 -14y+14y

32y = 40

32y/32 = 40/32

y = $\frac{5}{4}$

5. Substitute the new y-value into the simplified expression x = 2y:

x = 2(5/4)

x = $\frac{5}{2}$

hope this helps!

7 0

2 years ago

25 points, look at the picture.

attashe74 [19]

Answer:

1080

Step-by-step explanation:

PEMDAS says multiply and divide from left to right

9*5*6*3÷3*4*6÷6

45*6*3÷3*4*6÷6

270*3÷3*4*6÷6

810÷3*4*6÷6

270*4*6÷6

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6 0

3 years ago

Find the volume of a HEMIsphere <br> a radius of 4.

pentagon [3]

Answer:

honestly math is my worst subject but i think its 2 im really srry i think thats wrong tho

Step-by-step explanation:

6 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago