Three students want to estimate the mean backpack weight of their schoolmates. To do this, they each randomly chose 8 schoolmates and weighed their backpacks. Then as per the given sample data,
(a) The sample means of the backpacks are: 6.375,6.375,6.625
(b) Range of sample means: 0.25
(c)The true statement is: The closer the range of the sample means is to 0, the less confident they can be in their estimate.
For the first sample, mean= 6.375
For the second sample, mean= 6.375
For the third sample, mean= 6.625
Range of sample means=Maximum Mean- Minimum Mean
= 6.625 - 6.375
= 0.25
The students will estimate the average backpack weight of their classmates using sample means, the true statement is:
The closer the range of the sample means is to 0, the more confident they can be in their estimate.
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To get the maximum height, we first determine the time at which this maximum height is attained by differentiating the given equation and equating the differential to zero.
h(t) = -0.2t² + 2t
Differentiating,
dh(t) = -(0.2)(2)t + 2 = 0
The value of t is equal to 5. Substituting this time to the original equation,
h(t) = -0.2(5²) + 2(5) = 5 ft
Thus, the maximum height is 5 ft and since it will take 5 seconds for it to reach the maximum height, the total time for it to reach the ground is 10 seconds.
Answers: maximum height = 5 ft
time it will reach the ground = 10 s
The dimensions of the rectangle is 2.45 m by 5/8 m
thus the area will be:
A=length*width
A=2.45×5/8
A=1.53125 m²
Perimeter will be:
P=2(L+W)
P=2(2.45+5/8)
P=2(3.075)
P=6.15 m
Equation of the circle:
Step-by-step explanation:
The equation of a circle is given by
where
are the coordinates of the center of the circle
r is the radius of the circle
For the circle in this problem, we know that:
(5,4) are the coordinates of the center
We also know that the circle passes through the point (-3,2), therefore we can calculate the radius as the distance between the point on the circle and the center of the circle:
Therefore, the equation of the circle is:
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The width and height of Talia's Scale drawing are :
- Width = 4.35 in
- Height = 5.7 in
We can obtain the actual length of the side of the house from Mike's drawing :
- Mike's scale = 3 ft to 1 in
Actual measurements:
- Scale ratio × model drawing
- Height, h = 9.5 × 3 = 28.5 feets
- Width, w = 7.25 × 3 = 21.75 feets
Measurement of Talia's Scale drawing :
- Talia's scale = 5 ft to 1 in
- Actual measurement ÷ scale
- Height = 28.5 ÷ 5 = 5.7 in
- Width = 21.75 ÷ 5 = 4.35 in
The width and height of Talia's scale drawing are 5.7 and 4.35 respectively.
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