If the equation is
![7\sin^2x-14\sin x+2=-5](https://tex.z-dn.net/?f=7%5Csin%5E2x-14%5Csin%20x%2B2%3D-5)
then rewrite the equation as
![7\sin^2x-14\sin x+7=0](https://tex.z-dn.net/?f=7%5Csin%5E2x-14%5Csin%20x%2B7%3D0)
Divide boths sides by 7:
![\sin^2x-2\sin x+1=0](https://tex.z-dn.net/?f=%5Csin%5E2x-2%5Csin%20x%2B1%3D0)
Since
, we can factorize this as
![(\sin x-1)^2=0](https://tex.z-dn.net/?f=%28%5Csin%20x-1%29%5E2%3D0)
Now solve for <em>x </em>:
![\sin x-1=0](https://tex.z-dn.net/?f=%5Csin%20x-1%3D0)
![\sin x=1](https://tex.z-dn.net/?f=%5Csin%20x%3D1)
![\implies\boxed{x=\dfrac\pi2+2n\pi}](https://tex.z-dn.net/?f=%5Cimplies%5Cboxed%7Bx%3D%5Cdfrac%5Cpi2%2B2n%5Cpi%7D)
where <em>n</em> is any integer.
If you meant sin(2<em>x</em>) instead, I'm not sure there's a simple way to get a solution...
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Answer:
7^4
Step-by-step explanation:
7^12 / 7^8
We know that a^b / a^c = a^(b-c)
7^(12-8)
7^4