solution:
P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68
hence probability that she was enrolled in Dr. J's section given passed
=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706
19 is the answer 4+5(3)= 4+15=19
X = 5
AE and congruent to EC
If she used all of her yarn, she'd have 24 pieces. If she wanted 1.25 left, she'd have ten less because 24 • .125 = 8, and 1/4 of eight = 2, and 2 + 8 = 10.
So she'd have 14 pieces.
