The answer i would believe is to be true.
So, I came up with something like this. I didn't find the final equation algebraically, but simply "figured it out". And I'm not sure how much "correct" this solution is, but it seems to work.
![f(x)=\sin(\omega(x))\\\\f(\pi^n)=\sin(\omega(\pi^n))=0, n\in\mathbb{N}\\\\\\\sin x=0 \implies x=k\pi,k\in\mathbb{Z}\\\Downarrow\\\omega(\pi^n)=k\pi\\\\\boxed{\omega(x)=k\sqrt[\log_{\pi} x]{x},k\in\mathbb{Z}}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csin%28%5Comega%28x%29%29%5C%5C%5C%5Cf%28%5Cpi%5En%29%3D%5Csin%28%5Comega%28%5Cpi%5En%29%29%3D0%2C%20n%5Cin%5Cmathbb%7BN%7D%5C%5C%5C%5C%5C%5C%5Csin%20x%3D0%20%5Cimplies%20x%3Dk%5Cpi%2Ck%5Cin%5Cmathbb%7BZ%7D%5C%5C%5CDownarrow%5C%5C%5Comega%28%5Cpi%5En%29%3Dk%5Cpi%5C%5C%5C%5C%5Cboxed%7B%5Comega%28x%29%3Dk%5Csqrt%5B%5Clog_%7B%5Cpi%7D%20x%5D%7Bx%7D%2Ck%5Cin%5Cmathbb%7BZ%7D%7D)
Answer:
Option A
Step-by-step explanation:
⅗ ÷ ⅘
⅗ × 5/4
= 3/4
<h2>HOPE IT HELPS</h2>
Both the train will meet after 36 minutes.
<h3>Concept:</h3>
- To find when both the train will meet again at the same time, we need to find the LCM of the frequency.
<h3>How to solve the given question?</h3>
- Frequency of express train = 9 minutes = 3 × 3
- Frequency of local train = 12 minutes = 2 × 2 × 3
- LCM = 2 × 2 × 3 × 3 = 36
Thus, both the train will meet after 36 minutes.
Learn more about LCM here:
brainly.com/question/21504246
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