We know that
[volume of a sphere]=(4/3)*pi*r³-------> r=∛[(3*Volume)/(4*pi)]
r=∛[(3*Volume)/(4*pi)]------> r=∛[(3*3052.08)/(4*pi)]----> r=∛729
r=9 cm
[volume of a cylinder]=pi*r²*h
r=9 cm
h=2*r----> 2*9 -----> 18cm
[volume of a cylinder]=pi*r²*h----->pi*9²*18---> 4578.12 cm³
the answer is
4578 cm³
<span>Equation:
0.15x + 0.10(5-x) = 0.11*5
---
Multiply thru by 100:
15x + 10*5 - 10x = 11*5
---
5x = 5
x = 1 liter (amt. 15% oj needed)
----
5-x = 4 liters (amt of 10% oj needed)
======</span>
You have two unknown rates, so we need to develop two equations to solve for these unknowns (based on the information given on the problem statement):
5x + 10y = 725
x + y = 100
By substitution, we get:
5x + 10(100 - x) = 725
5x + 1000 - 10x = 725
-5x = 725 - 1000
-5x = -275
x = -275/-5 = 55
100 - 55 = 45
Thus:
The mechanic who worked for 5 hours charged his time at $55/hr, and the mechanic who worked for 10 hours charged his time at $45/hr.
To verify, plug and chug the results back into the original equations:
5(55) + 10(45) = 725
275 + 450 = 725
725 = 725 [OK]
55 + 45 = 100 [OK]
Answer:
A. `1/2` foot
Step-by-step explanation:
The computation of the width of the box is shown below:
15 ÷ 28 = (5 ÷ 7)(1 1 ÷ 2)(width)
15 ÷ 28 = (5 ÷ 7)(3 ÷ 2)width
15 ÷ 28 = (15 ÷ 14)width
(15 ÷ 28) ÷ (15 ÷ 14) = width
(15 ÷ 28) × (14 ÷ 15) = width
w = 14 ÷ 28
= 1 ÷ 2 ft
You would divide miles to hours amd get 57.5
