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3 years ago

Functions f(x) and g(x) are shown below:

Mathematics

1 answer:

ANTONII [103]3 years ago

7 0

Answer:

I just took the test it's left by 4 units

❤️

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What is my number my number is a perfect square the only prime number in it prime factorization is 2 my number is a factor of 32

WITCHER [35]

Nmkndj;n;bnjngfndjknh;rtnh 216g6n
543646245mh.nrkjhgjn.kjgnrjkbuhjtbyultkngu;njktnj totm,my fotrtunanhioubgrviuebglryrhntonm my forytunabjvfdjkfvghyulbfwqlcbherovbegiunj gtjgbasyhj.bsf.fjkbgilhbjbhfljbvhuj

4 0

3 years ago

What is the answer??

lorasvet [3.4K]

Answer:

80°

Step-by-step explanation:

Triangle ABC and CYZ are similar so the angles would also be same

8 0

3 years ago

B) What should be subtracted from -7mn + 2m² + 3n² to get<br>m²+ 2mn + n²?<br>please help

Hitman42 [59]

Answer: m²-9mn+2n²

Step-by-step explanation: make use of BODMAS strategy. Let the unknown be x.

-7mn+2m²+3n²-x= m²+2mn+n². Since we are concerned about getting the unknown,let's try to collect the like terms.

-7mn+2m²+3n²-(m²+2mn+n²)= x

-7mn+2m²+3n²-m²-2mn-n²= x

-7mn-2mn+2m²-m²+3n²-n²=x

-9mn+m²+2mn= x

X= m²-9mn+2n²

6 0

4 years ago

To the nearest tenth, find the perimeter of ABC with vertices A(-1,4), B(-2,1) and C(2,1). show your work

liubo4ka [24]

we have to firstly apply the distance formula to find the length of sides of the triangle

distance formula = $\sqrt{(x_{2} -x_{1})^2 +(y_{2}- y_{1})^2}$

So length AB = $\sqrt{(-2-(-1))^2+(1-4)^2}= \sqrt{1 +9}=\sqrt{10}$

BC= $\sqrt{(2-(-2))^2+(1-1)^2}= \sqrt{16+0}=4$

AC = $\sqrt{(2-(-1))^2+ (1-4)^2}= \sqrt{9+9}=\sqrt{18}=3\sqrt{2}$

Now perimeter = AB+BC+AC = $\sqrt{10}+4+3\sqrt{2}$

Plug in calculator

perimeter= 11.4 units

7 0

3 years ago

If someone ran 14.6 miles from their house and then they are now 9.8 miles from their house and finally they are 5.3 miles away

elixir [45]

Answer:

<u>10.1 miles</u> far is their house.

Step-by-step explanation:

Given:

If someone ran 14.6 miles from their house and then they are now 9.8 miles from their house and finally they are 5.3 miles away.

Now, to find the distance is far from their house.

14.6 miles distance they ran from their house.

So, they are far from house = $14.6\ miles.$

Then, 9.8 miles they are from their house.

So, they are far from house = $14.6-9.8\ miles=4.8\ miles.$

And, finally 5.3 miles away from their house.

So, now they are far from house = $4.8+5.3=10.1\ miles.$

Therefore, 10.1 miles far is their house.

6 0

3 years ago