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3 years ago

Someone please help me this is due tomorrow!!!

Mathematics

1 answer:

Murljashka [212]3 years ago

3 0

Let me know if you can see this photo

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Simplify (-343,000) 1/3

bixtya [17]

-343,000 x 1/3 = -114,333.333333333219

3 0

3 years ago

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

$y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

The rumor reaches 80% at 8.48 days.

8 0

3 years ago

(NEED HELP WITH NUMBER 1!!!)

alexandr1967 [171]

Answer:

35 ia the answer sorry if im wrong

7 0

3 years ago

Please help me solve this please

nlexa [21]

Answer:

2. (-3f)

3. (4f)

4. x - 11 (not sure if this one is correct)

Step-by-step explanation:

Move -3 to the left of f = -3f

Move 4 to the left of f = 4f

f(x)=x+11 f ( x ) = x + 11

8 0

2 years ago

Please help me! I will mark brainliest!

Elenna [48]

Answer:

Your picture didn't load?

Step-by-step explanation:

3 0

3 years ago

Someone please help me this is due tomorrow!!!​

Someone please help me this is due tomorrow!!!