Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
<u>Answer:</u>
The plane's resultant vector is 890.3 miles, at an angle of 59.5° west of north.
<u>Step-by-step explanation:</u>
• To find the magnitude of the resultant vector, we have to use Pythagoras's theorem:
where:
a ⇒ hypotenuse (= resultant vector = ? mi)
b, c ⇒ the two other sides of the right-angled triangle (= 452 mil North, 767 mi West).
Using the formula:
resultant² = 
⇒ resultant = 
⇒ resultant = 890.3 mi
• To find the direction, we can find the angle (labeled <em>x</em> in diagram) that the resultant makes with the north direction:
⇒ 
⇒ 
∴ The plane's resultant vector is 890.3 miles, at an angle of 59.5° west of north .
Answer:
11.8in^3
Step-by-step explanation:
i just had it
Answer:
about 5
Step-by-step explanation:
