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wlad13 [49]
3 years ago
14

Please help me solve this #algebra #algebra1

Mathematics
1 answer:
Vesna [10]3 years ago
3 0

Answer:

h = 430

Step-by-step explanation:

1290 = h/10 + h/5             Make h/5 into something that is something / 10

1290 = h/10 + 2h/(5*2)     Clean up the brackets.

1290 = h/10 + 2h/10         Add the right.

1290 = 3h/10                    Multiply both sides by 10

1290*10 = 10(3h/10)          

12900 = 3h                       Divide both sides by 3

h = 430

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A poultry farmer wishes to estimate the average incubation period (the number of days between a hen laying her egg and the time
sergiy2304 [10]

Answer:

49 eggs.

Step-by-step explanation:

The formula for Margin of Error =

z × standard deviation/√number of samples

z = z score of 98% confidence interval = 2.326

Margin of Error = Half a day = 1/2day = 0.5 day

Standard deviation = 1.5 days

Number of samples = number of eggs he needs to sample = unknown.

Imputing these above values into the formula

Margin of Error = z × standard deviation/√number of samples

0.5 = 2.326 × 1.5/√n

Cross Multiply

0.5 × √n = 2.326 × 1.5

√n = 2.326 × 1.5/0.5

√n = 3.489/0.5

√n = 6.978

Square both sides

(√n)² = 6.978²

n = 48.692484

n ≈ Approximately to the nearest whole number = 49

Therefore, the number of eggs he needs to sample to create the desired interval is approximately to the nearest whole number 49 eggs

8 0
3 years ago
Pls help, I need to turn it in quick!!
Paladinen [302]

Answer:

I think it is C but I am not 100% sure

Step-by-step explanation:


7 0
2 years ago
Parallelogram ABCD is given. Draw line EF so that it goes through the vertex A. Point E lies on the side BC and point F lies on
tresset_1 [31]

Answer:

The proof is explained step-wise below :

Step-by-step explanation :

For better understanding of the solution see the attached figure :

Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC

Now, F lies on the extension of DC. So, AB ║ DF

To Prove : ΔABE is similar to ΔFCE

Proof :

Now, in ΔABE and ΔFCE

∠ABE = ∠FCE ( alternate angles are equal )

∠AEB = ∠FEC ( Vertically opposite angles )

So, by using AA postulate of similarity of triangles

ΔABE is similar to ΔFCE

Hence Proved.

7 0
3 years ago
Can I know the answer I'm so confused
77julia77 [94]
You didn't post a question.
3 0
2 years ago
Read 2 more answers
Please help I'll give brainiest
Irina18 [472]
What do you need help on exactly?
6 0
3 years ago
Read 2 more answers
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