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3 years ago

Please help me solve this #algebra #algebra1

Mathematics

1 answer:

Vesna [10]3 years ago

3 0

Answer:

h = 430

Step-by-step explanation:

1290 = h/10 + h/5 Make h/5 into something that is something / 10

1290 = h/10 + 2h/(5*2) Clean up the brackets.

1290 = h/10 + 2h/10 Add the right.

1290 = 3h/10 Multiply both sides by 10

1290*10 = 10(3h/10)

12900 = 3h Divide both sides by 3

h = 430

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AEFG - ALMN. Find the ratio of AEFG to ALMN. A)1:4 B)1:2 C)2.1 D)4:1

vovikov84 [41]

Answer:

C)2 : 1

Step-by-step explanation:

AEFG ≈ ALMN

FG / MN = 4 / 2 = 2/1

So the ratio of AEFG to ALMN = 2 / 1 or 2 : 1

6 0

3 years ago

Jessie finishes 2/5

Mashcka [7]

Answer: Jessie still has 3/10 left.

Step-by-step explanation:

Convert 2/5 into tenths by multiplying by 2.

2/5 x 2 = 4/10

3/10 + 4/10 = 7/10

The entirety of her homework is 10/10 so do

10/10 - 7/10 = 3/10

She has 3/10 left.

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2 years ago

Which of the following are not congruence theorems for right triangles? Check all that apply.

Lera25 [3.4K]

Answer:

c) HH E)AA

Step-by-step explanation:

Two right angles can be proved congruent by LA,LL,HA,HL properties.

HH and AA are not congruence property.

Two triangles can be proved similar by AA property. All congruent triangles are similar but all similar triangles are not similar.Hence right triangles can not be proved congruent by AA property.

Among the options given Option C and E are not congruence property.

7 0

3 years ago

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PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi

Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

$Hypotenuse^2=Base^2+Perpendicular^2$

⇒ $5^2=3^2+4^2$

Let a, b, c forms a Pythagorean triplet

$a^2+b^2=c^2$

Multiplied by 4 on both sides

⇒ $4a^2+4b^2=4c^2$

⇒ ${2a}^2+{2b}^2={2c}^2$

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

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3 years ago

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AVprozaik [17]

Answer:

the answer is 1000 metres

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3 years ago

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