Please help me idk this
1 answer:
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Answer:
[a]. check attachment.
[b]. It can not be said that the difference is ascribed to chance as P-value = 0.001 which is less than <<0.05. That is P-value = 0.001 <<0.05.
Step-by-step explanation:
Without mincing words let's dive straight into the solution to the question above.
[a]. The drawing showing the histogram of bacterial endotoxin levels is given in the attached picture.
KINDLY NOTE: The data is right-skewed.
[b]. ALLERGIC MEAN SE MEAN STDEV N
FALSE 1510 251 1789 251
TRUE 530 109 343 10
False - true = difference in a.
Hence, 80 = estimated difference.
For the difference, 95% CI = (434, 1527).
DF = 58, P-value = 0.001, and the T value = 3.59.
Therefore, It can not be said that the difference is ascribed to chance as P-value = 0.001 which is less than <<0.05. That is P-value = 0.001 <<0.05.
Answer:
There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they believe in reincarnation, or they do not believe. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution:
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
In this problem
There are 5 adults, so
60% believe in reincarnation, so
What is the probability that exactly 4 of the selected adults believe in reincarnation?
This is P(X = 4).
There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.