All categories

3 years ago

Please foil (x^2 - (1/5x^2))^2

1 answer:

8 0

(x² - (1/5x²))²

Using (a-b)² = a²-2×ab+b²

(x²)² -2x²×(1/5x)² + (1/5x²)²

x⁴ -2x⁴ + 1/25⁴

We developed the fraction to obtain the lowest common denominator

x⁴/1 - 2x⁴/5 +x⁴/25

25×(X⁴)/25×1 - 5×(2x⁴)/5×5 + x⁴/25

25×⁴/25 - 10x⁴/25 + x⁴/25

{25×⁴- 10x⁴ + 1x⁴}/25

{26×⁴- 10x⁴}/25

{26×⁴- 10x⁴}/25

16x⁴/25

You might be interested in

Se dau punctele coliniare A,B,C cu distanta AB=30 BC=15 .Calculati distanta dintre AsiC.Catr soluti are proclrma?

Arlecino [84]

36 is your answer to that question

5 0

3 years ago

Write the steps for how to use a number line to multiply a 2 digit number by 20. Give an example

lidiya [134]

Draw the number line then put the numbers on the number line by twos. Fore example, 2-4-6-8-10

8 0

3 years ago

[79 points if correct] Help me with any 4 questions! Please !!!!

Anarel [89]

Answer:

(BEFORE YOU SUBMIT IT, PLEASE READ THE WARNING)

QUESTION EIGHT: 2690

QUESTION NINE: 120

QUESTION ELEVEN: 12.5

QUESTION FOURTEEN: 24

Step-by-step explanation:

WARNING!! FOR QUESTIONS WITH INTEREST: I do not know if interest is good or bad (if you get money, or if you lose money. I counted interest as making money, but if you are sure it's not, contact me in the comments and I will solve it again! :)

may 3rd -> july 15th = 73 days

500*0.06 = 30

30 = how much he makes in one day (so he has 530 after 1 day)

30*73 = 2190

500 + 2190 = 2690

210/7 = 30

1% for 3 years = 30

1% for 1 year = 10

100% for 1 year = 1000

2000*0.06 = 120

11.

54,000*0.08 = 4320

54,000/4320 = 12.5

14.

5000*6.26% = 312.5

7500/312.5 = 24

5 0

3 years ago

A random sample of 15 employees was selected. The average age in the sample was 31 years with a variance of 49 years. Assuming a

vova2212 [387]

Answer:

Assuming ages are normally distributed, the 98% confidence interval for the population average age is [26.3, 35.7].

Step-by-step explanation:

We have to construct a 98% confidence interval for the mean.

The information we have is:

- Sample mean: 31

- Variance: 49

- Sample size: 15

- The age is normally distributed.

We know that the degrees of freedom are

$k=n-1=15-1=14$

Then, the t-value for a 98% CI is t=2.625 (according to the t-table).

The standard deviation can be estimated from the variance as:

$s=\sqrt {s^2}=\sqrt{49}=7$

The margin of error is:

$E=t_{14}*s/\sqrt{n}\\\\E=2.625*7/\sqrt{15}=18.375/3.873=4.7$

Then, the CI can be constructed as:

$M-t*s/\sqrt{n}\leq\mu\leq M+t*s/\sqrt{n}\\\\31-4.7\leq \mu \leq 31+4.7\\\\26.3\leq \mu \leq 35.7$

5 0

3 years ago

Which statement best explains the relationship

Thepotemich [5.8K]

Answer:

they are perpendicular because they have slopes that are negative reciprocals

Step-by-step explanation:

4 0

3 years ago