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zmey [24]
3 years ago
11

How do you convert a division word problem into a fraction?

Mathematics
2 answers:
anzhelika [568]3 years ago
5 0
I *think* the dividend is the numerator and the divisor is the denominator.

Dividend/Denominator
baherus [9]3 years ago
4 0
For example: if the word problem were simply "4 divided by 2", the fraction would be a 4 with a line underneath and the 2 underneath that.

I hope I made this possible to understand... let me know if you were referring to something else!
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Divide 3 1/2 divided by 1 2/3
dybincka [34]

Answer:

2 1/10=

Answer: 2.1

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
I need help on these questions please
Paraphin [41]

Answer:

Step-by-step explanation:

1). In ΔABC,

   For angle A as a reference angle,

   Opposite side of ∠A → BC

   Adjacent side of ∠A → AC

   Hypotenuse → AB

2). By using tangent ratio in ΔYWZ,

    tan(72°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

    tan(72°) = \frac{12}{x}

    x = \frac{12}{\text{tan}(72)}

    x = 3.899

    x ≈ 3.9

3). By using sine rule in ΔKNM,

    tan(x°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

    tan(x) = \frac{20}{58}

    x = \text{tan}^{-1}(\frac{20}{58} )

    x = 19.03

    x ≈ 19.0°

4). By applying cosine ratio in ΔJKF,

    tan(70°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

    tan(70) = \frac{60}{x}

    x = \frac{60}{\text{tan}(70)}

    x = 21.838

    x ≈ 21.8

7 0
3 years ago
Which of the following is the method used to determine whether or not a proportion is true?
sdas [7]

Answer:

Cross multiplication is the method  used to determine whether or not a proportion is true.

Explanation:

If you know one ratio in a proportion, you can use that information to find values in the other equivalent ratio.

Cross multiplication is the method used to determine whether or not a proportion is TRUE.

For example, if a bowl of fruit contains 10 oranges and 8 lemons, then the ratio of oranges to lemons is 10  is to 8 (that is, 10 : 8 ), which is equivalent to the ratio 5:4).

7 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
erma4kov [3.2K]

Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

n = 5

(h,i,j,k,m) implies that:

r = 5

Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

6 0
3 years ago
How do I complete a table for this word math problem
Rufina [12.5K]
There isn’t a picture but hopefully I can help u
4 0
3 years ago
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