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3 years ago

Find the volume of the rectangular prism. The volume is cm? 8 cm 5 cm 9 cm

Mathematics

2 answers:

dedylja [7]3 years ago

6 0

Answer:

360 cm

Step-by-step explanation:

volume= length x width x height

8*5*9=360 cm

jasenka [17]3 years ago

5 0

Answer:

360cm

Step-by-step explanation:

All you have to do is multiply the numbers.

To break it up, you can first multiply 8 and 5.

8 x 5 = 40.

Now that you have 40, multiply that by 9.

40 x 9 = 360.

Apply the unit: cm

360cm is your answer.

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Using the quadratic equation formula to solve 7x^2-x=7, what are the values of x

Gennadij [26K]

quadratic formula:

x = -b ± √(b² - 4ac)

7x² - x = 7

subtract 7 from both sides:

7x² - x - 7 = 0

plug values into the quadratic formula:

x = -(-1) ± √((-1)²- 4(7)(-7))

2(7)

simplify:

x = 1 ± √(197)

8 0

3 years ago

Find the discriminant and the number of real roots for this equation.

GuDViN [60]

Answer:

Step-by-step explanation:

To find the discriminant you do b^2-4(a)(c), which in this case gives you -28. If your discriminant is less than zero, you will have no real roots.

8 0

3 years ago

he one‑sample t statistic from a sample of n = 23 observations for the two‑sided test of H 0 : μ = 15 versus H α : μ > 15 has

DedPeter [7]

Answer:

$t = 2.24$

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

Step-by-step explanation:

Data given and notation

$\bar X$ represent the mean height for the sample

$s$ represent the sample standard deviation

$n=23$ sample size

$\mu_o =15$ represent the value that we want to test

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

For this case the statistic is given:

$t = 2.24$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

5 0

3 years ago

2 times 5 times 10 to the 5th power

xxMikexx [17]

10 to the 5th power is 100,000. 2 X 5 is 10.
10 X 100,000 is one million.

the answer is 1,000,000. (one million)

5 0

3 years ago

Read 2 more answers

The number of defective units in a production run of 850 circuit boards are normally distributed with 21 defective units and 3 d

Katen [24]

Answer:

82%

Step-by-step explanation:

We let the random variable X denote the number of defective units in the production run. Therefore, X is normally distributed with a mean of 21 defective units and a standard deviation of 3 defective units.

We are required to find the probability, P(17 < X < 25), that the number of defective units in the production run is between 17 and 25.

This can be carried out easily in stat-crunch;

In stat crunch, click Stat then Calculators and select Normal

In the pop-up window that appears click Between

Input the value of the mean as 21 and that of the standard deviation as 3

Then input the values 17 and 25

click compute

Stat-Crunch returns a probability of approximately 82%

Find the attachment below.

5 0

3 years ago