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serg [7]
3 years ago
8

If the temperature outside is 297 what is this temperature in degrees celsius

Chemistry
1 answer:
Monica [59]3 years ago
6 0

Answer:

147.222 degrees C

Explanation:

assuming its  297 F it should be correct

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What is the final volume of a 400 ML sample that is subjected To a temperature change from 22 Celsius to 30 Celsius in a pressur
bija089 [108]

Answer:

The answer to your question is  V2 = 867.3 mL

Explanation:

Data

Volume 1 = V1 = 400 ml

Temperature 1 = T1 = 22°C

Pressure 1 = P1 = 760 mmHg

Volume 2 = V2 = ?

Temperature 2 = T2 = 30°C

Pressure 2 = P2 = 360 mmHg

Process

1.- Convert Celsius to Kelvin

T1 = 22 + 273 = 295°K

T2 = 30 + 273 = 303°K

2.- Use the Combined gas law

              P1V1/T1 = P2V2/T2

- Solve for V2

            V2 = P1V1T2 / T1P2

- Substitution

            V2 = (760 x 400 x 303) / (295 x 360)

- Simplification

            V2 = 92112000 / 106200

-Result

            V2 = 867.3 mL

8 0
3 years ago
Some scientists believe that comets originate from the...​
deff fn [24]

Answer:

Scientists believe that comets are the debris left from the solar nebula which condensed to form the Sun and planets in our solar system. Most comets are thought to originate in a huge cloud called the Oort Cloud. ... Comets follow a regular orbit around the Sun.

Hope this helps! :)

Explanation:

3 0
4 years ago
The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?
Aloiza [94]

Answer:

0.0468 g.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

<em>∴ (a-x) = 12/256.34 = 0.0468 g.</em>

8 0
3 years ago
What is the law of inertia?
Pachacha [2.7K]
B is the law of inertia
3 0
3 years ago
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Which principal energy level can hold a maximum of 18 electrons?
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3rd level would able to hold a max of 18 elelctrons


5 0
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