All categories

4 years ago

Cu(NO3)2 + Zn (s) → Cu (s) + Zn(NO3)2 is an example of which type of reaction?

Chemistry

1 answer:

labwork [276]4 years ago

4 0

Single replacements since cu is being replaced by zn

You might be interested in

Suppose two chemicals are reacted together. It takes 1000 kJ of energy to break the bonds of the reactants and 850 kJ of energy

Deffense [45]

The true statement is :
B.The reaction will need an external energy source to proceed. It requires 150kJ more for it to take place. The difference between the energy consumed and the energy produced is 150kJ.

4 0

4 years ago

Read 2 more answers

The stability of an atom is determined by the

Tcecarenko [31]

Ratio of neutrons to protons and number of electrons in the outer shell

4 0

3 years ago

Read 2 more answers

Which order shows the size of the inner planets from smallest to largest

elixir [45]

Answer:

PLUTO

MERCURY

MARS

VENUS

EARTH

NEPTUNE

URANUS

SATURN

JUPITER

Explanation:

4 0

3 years ago

Read 2 more answers

Why the standard enthalpy change of hydration of copper sulphate cannot be measured directly ?

Juliette [100K]

It is difficult to measure the enthalpy change of hydration accurately in a direct way because the hydration process can't be controlled directly. Instead, anhydrous and hydrated copper(II) sulfate can be dissolved in water. Each 'route' produces a solution of hydrated copper(II) sulfate.

5 0

3 years ago

How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g･°C) as it changes temperature from 23.0°

kotykmax [81]

Answer:

$\boxed {\boxed {\sf 1076.196 \ Joules}}$

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

$q=mc\Delta T$

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

The change in temperature is the difference between the initial temperature to the final temperature.
The temperature changes from 23.0°C to 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
ΔT= final temperature - initial temperature
ΔT= 67°C - 23°C
ΔT= 44°C

Now we know all the values.

m= 26.3 g
c= 0.930 J/g °C
ΔT= 44°C

Substitute the values into the formula.

$q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)$

Multiply the first two numbers together. The units of grams cancel.

$q= 24.459 \ J/ \textdegree C \times 44 \textdegree C$

Multiply again. This time, the units of degrees Celsius cancel.

$q=1076.196 \ J$

1076.196 Joules of heat will be absorbed by the piece of aluminum.

4 0

3 years ago