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Alik [6]
3 years ago
13

A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. Each

small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. There were twice as many large boxes shipped as small boxes shipped and the total weight of all boxes was 1435 pounds. Determine the number of small boxes shipped and the number of large boxes shipped.
Mathematics
1 answer:
Jobisdone [24]3 years ago
5 0

Answer:

your... syllabus is different from mine....

Step-by-step explanation:

which class u study

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When taking skinfold measurement readings only one attempt per site is necessary for an accurate reading.a. Trueb. False
Eva8 [605]

Answer: False

Step-by-step explanation: Skinfold measurements is one of the oldest ways of measuring a person's fat percentage,it's usually taken in specific areas of the body where there are Skinfolds,while taking this measurements it is expected that the person taking it does the average of 2or more repeated measurements in order to ensure that the actual thickness of that area of the body is correctly entered.

It is specifically taken from the right side of the body,where the person pinches out the Skinfolds away from the body by attaching a caliper ,this is to ensure that only the fatty laters are considered, it is mainly presented in percentage.

3 0
3 years ago
Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with
skad [1K]

Parameterize S by the vector function

\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle

The integral of the field over S is then

\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv

\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv

\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}

8 0
2 years ago
I don’t understand this
SashulF [63]

Answer:

9 to the 5th power

Step-by-

7 0
3 years ago
Read 2 more answers
65 points! PLEASE HELP!!!
kow [346]

Answer:

Holly's score is an outlier because the mean of the data is 83, and 30 is very far then 83.

The mean is 83

The median is 87

Removing the outlier change the mean because the mean became higher.

The mean was most affected by the outlier because the mean changed to 86. 31

8 0
3 years ago
Find all the missing values to make the equation true
Georgia [21]

The missing value in the logarithm are as follows:

  • log₃ 7 - log₃ 2 = log₃ (7 / 2)
  • log₉ 7 + log₉ 4 =  log₉ 28
  • log₆ 1 / 81  =  
  • - 4 log₆ 3

<h3>How to solve logarithm?</h3>

Using logarithm rule,

logₐ b - logₐ c = logₐ (b / c)

logₐ b + logₐ c = logₐ (b × c)

Therefore,

log₃ 7 - log₃ 2 = log₃ (7 / 2)

log₉ 7 + log₉ 4 = log₉ (7 × 4) =  log₉ 28

log₆ 1 / 81 = log₆ 81⁻¹ = log₆ 3⁻⁴ =  - 4 log₆ 3

learn more on logarithm here: brainly.com/question/24515212

#SPJ1

4 0
2 years ago
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